Python For 循环 - 枚举

Question

你能帮我解决这个问题吗？尝试了以下代码但不起作用。我正在尝试打印出附加的输出。提前致谢。

num_display = int(input('Please enter how many numbers you would like displayed: '))
inc_value = int(input('Please enter the increment value: '))
num_counter = 1
num_sequence = range(1, num_display + 1 , inc_value)
value_counter = range(1, num_counter, inc_value)

for each_num in num_sequence:
    print(f'Counter: {num_counter} value: {each_num}')
    num_counter = num_counter + 1
    value_counter = value_counter + 1
print("Bye.")

输出应该是什么样的

Please enter how many numbers you would like displayed: 12
Please enter the increment value: 3
Counter: 1 value: 1
Counter: 2 value: 4
Counter: 3 value: 7
Counter: 4 value: 10
Counter: 5 value: 13
Counter: 6 value: 16
Counter: 7 value: 19
Counter: 8 value: 22
Counter: 9 value: 25
Counter: 10 value: 28
Counter: 11 value: 31
Counter: 12 value: 34
Bye.

我更改了代码以满足其他条件，但在将 str 转换为 int 后出现此错误：第 11 行，在 num_sequence = 范围 (1,stop_value,inc_value) 类型错误：'str' 对象不能解释为整数

我的代码：

num_display = input('Please enter how many numbers you would like displayed: ').strip()
inc_value = input('Please enter the increment value: ').strip()
zero_value = 0

if num_display.isdigit() and inc_value.isdigit():
    if int(num_display) != zero_value or int(inc_value) != zero_value:
        stop_value = int(num_display) * int(inc_value)
        num_sequence = range(1,stop_value,inc_value)
        for num_counter, each_num in enumerate(num_sequence):
                        print(f'Counter: {num_counter + 1} value: {each_num}')
        print('Bye.')
    else:
        print("I can't increment in steps of 0.")     

else:
    print('Positive non zero integers only please.')

我使用下面的方法让它工作，但它没有正确打印另一个，请看截图：

num_display = input('Please enter how many numbers you would like displayed: ').strip()
inc_value = input('Please enter the increment value: ').strip()
zero_value = 0

if num_display.isdigit() and inc_value.isdigit():
    if int(num_display) != zero_value and int(inc_value) != zero_value:
        stop_value = int(num_display) * int(inc_value)
        num_sequence = range(1, int(stop_value), int(inc_value))
        for num_counter, each_num in enumerate(num_sequence):
                        print(f'Counter: {num_counter + 1} value: {each_num}')
        print('Bye.')
    else:
        print("I can't increment in steps of 0.")     

else:
    print('Positive non zero integers only please.')

working but not printing 5 on the other test

Answer 1

您的代码存在一些问题。 range() 会在每次迭代后自动将计数器增加 inc_value，因此不要在循环中手动更新该计数器。

另外还有一道数学题。如果你想打印一个数字 num_display 次递增 inc_value 计算最后一个数字的公式（因此 range() 的 end 值）是 start_value + inc_value * num_display，而不是 num_display + 1。在你的情况下 start_value 是 1.

要以 pythonic 方式获取迭代次数，请使用 enumerate()。

num_display = int(input('Please enter how many numbers you would like displayed: '))
inc_value = int(input('Please enter the increment value: '))
start_value = 1
num_sequence = range(1, start_value + num_display * inc_value, inc_value)

for num_counter, each_num in enumerate(num_sequence):
    print(f'Counter: {num_counter + 1} value: {each_num}')
print("Bye.")

预期输出

Please enter how many numbers you would like displayed: 12
Please enter the increment value: 3
Counter: 1 value: 1
Counter: 2 value: 4
Counter: 3 value: 7
Counter: 4 value: 10
Counter: 5 value: 13
Counter: 6 value: 16
Counter: 7 value: 19
Counter: 8 value: 22
Counter: 9 value: 25
Counter: 10 value: 28
Counter: 11 value: 31
Counter: 12 value: 34
Bye.

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