在 Spring 引导中定位字符串字段时出错

Question

我试图通过数据库 (H2) 中的 CNPJ（巴西企业纳税人登记号）查找公司，但返回错误

{
 "timestamp": "2022-03-30T19:30:23.823+00:00",
 "status": 404,
 "error": "Not Found",
 "path": "/companies/cnpj/30101554000146"
}

我尝试过其他替代方法：

http://localhost:8080/companies/cnpj/'30.101.554/0001-46', http://localhost:8080/companies/cnpj/"30.101.554/0001- 46",

但错误仍然存在。我是这样实现的：

@Entity
@Table(name = "company")
 public class Company implements Serializable {

 private static final long serialVersionUID = 1L;

 @Id
 @GeneratedValue(strategy = GenerationType.IDENTITY)
 private Long id;

 private String name;
 @CNPJ
 private String cnpj;

//skipped
}

public interface CompanyRepository extends JpaRepository<Company,Long> {

 Optional<Company> findByCnpj(String cnpj);
}

public class CompanyDTO {
 private Long id;

 private String name;

 private String cnpj;

//skipped
}

@Service
@Transactionalpublic class CompanyService {

 @Autowired
 private CompanyRepository companyRepository;

 @Transactional(readOnly = true)
 public CompanyDTO findById(Long id) {
    Company resultado = companyRepository.findById(id).get();
    CompanyDTO dto = new CompanyDTO(resultado);
    return dto;
 }  

 @Transactional(readOnly = true)
 public CompanyDTO findByCnpj(String cnpf) {
    Optional<Company> resultado = companyRepository.findByCnpj(cnpf);
    CompanyDTO dto = new CompanyDTO(resultado.get());
    return dto;
    
 }
}

@RestController
@RequestMapping(value = "/companies")public class CompanyController {

 @Autowired
 private CompanyService companyService;


 @GetMapping(value = "/{id}")
 public CompanyDTO findById(@PathVariable Long id) {
    return companyService.findById(id);
 }

 @GetMapping(value = "/cnpj/{cnpj}")
 public CompanyDTO findByCnpj(@PathVariable String cnpj) {
    return companyService.findByCnpj(cnpj);
 }
}

预期输出为：

[
  {"id": 1,
   "nome": "Company 123",
   "cnpj": "30.101.554/0001-46"
  }
]

更新：

我将@GetMapping(value = "/cnpj/{cnpj}") 更改为@GetMapping(value = "/cnpj/**") 并且：

@GetMapping(value = "/cnpj/**")
     public CompanyDTO findByCnpj(HttpServletRequest request) {
        return companyService.findByCnpj(request.getRequestURI().split(request.getContextPath() + "/cnpj/")[1]);
     }

适合我！谢谢

Answer 1

如 here 所述，使用 spring-boot 时，带斜线的 pathParams 可能会非常棘手。这篇文章很好地解释了当您的 pathVariable 有斜杠时如何避免得到 error 404。

在 Spring 引导中定位字符串字段时出错

Error locating String field in Spring Boot

hibernate

jpa

spring-boot