我在 deck[i][j] 附近的第 11 行收到一条错误消息

Question

我在第 9 行代码中收到以下错误消息 (deck[i][j] = ...) 二进制 + 的无效操作数（具有“char *”和“char *”）。我该如何解决这个问题？

#include <stdio.h>

char* suit[4] = {"Hearts", "Diamonds", "Clubs", "Spades"};
char* face[13] = {"Ace", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine", 
"Ten", "Jack", "Queen", "King"};

 char* deck[4][13];

void initialiseDeck(){
for(int i = 0; i < 4; ++i)
    for(int j = 0; j < 13; ++j)
        deck[i][j] = face[j] + "of" + suit[i];
}

void display(){
for(int i = 0; i < 4; ++i)
    for(int j = 0; j < 13; ++j)
        printf("%17s\n", deck[i][j]);
}

void shuffleDeck(){

int shuffler[52];
for(int i = 0; i < 52; ++i) shuffler[i] = i;

for(int i = 0; i < 52; ++i){

    int ind = i+(rand()%(52-i));

    int deckI = ind/13;
    int deckJ = ind/13;

    swap(deck[i/13][i%13], deck[deckI][deckJ]);
}
}

Answer 1

我们来了！所以我添加了宏以使代码更具可读性，并且还编写了函数 create_card_name 这是它的作用：它为您的卡的全名分配内存并创建它：

#include <stdlib.h>
#include <stdio.h>
#include <string.h>


#define DECK_SIZE 52
#define SUIT_SIZE 4
#define FACE_SIZE 13


char *suit[SUIT_SIZE] = {"Hearts", "Diamonds", "Clubs", "Spades"};
char *face[FACE_SIZE] = {"Ace", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine",
                  "Ten", "Jack", "Queen", "King"};

char *deck[SUIT_SIZE][FACE_SIZE];

char * card_name_create(char* face, char* suit)
{
    size_t face_len = strlen(face);
    size_t suit_len = strlen(suit);
    size_t of_len = 4;
    char of[5] = " of ";
    // The size id the size of two strings, than the size of " of " and the '[=10=]'
    char * full_name = malloc(sizeof(char)*(face_len+suit_len+of_len+1));

    for (size_t i = 0; i < face_len; i++)
    {
        full_name[i] = face[i];
    }
    for (size_t i = face_len; i < face_len+of_len; i++)
    {
        full_name[i] = of[i-face_len];
    }
    for (size_t i = face_len+of_len; i < face_len+of_len+suit_len; i++)
    {
        full_name[i] = suit[i - (face_len+of_len) ];
    }
    full_name[face_len+of_len+suit_len] = '[=10=]';
    return full_name;
    
}

void initialiseDeck()
{
    for (int i = 0; i < SUIT_SIZE; i++)
    {
        for (int j = 0; j < FACE_SIZE; j++)
        {
            char * c = card_name_create(face[j],suit[i]);
            deck[i][j] = c;
        }   
    }
        
}

void display()
{
    for (int i = 0; i < SUIT_SIZE; i++)
    {
        for (int j = 0; j < FACE_SIZE; j++)
        {
            printf("%17s\n", deck[i][j]);
        }
    }        
}

另外，尽量不使用三重指针也是一件好事，你的套牌就是这种情况。您可以使用简单的指针实现所有字符串，并使用 % 循环遍历它们。

我在 deck[i][j] 附近的第 11 行收到一条错误消息

I'm getting an error message in line 11 near deck[i][j]

c

arrays

pointers