application/json 内容类型存储位置
application/json content type store location
内容类型的结果:“application/x-www-form-urlencoded” 存储在 Request.Form 中 Asp MVC.
但是 "application/json" 我找不到商店位置
这是我使用的代码:
ajax部分
// reading form data
var form = $("form")[0];
var formData = new FormData(form);
var object = {};
formData.forEach(function(value, key){
object[key] = value;
});
var data = JSON.stringify(object);
// ajax part
// POST application/json; charset=utf-8
$.ajax({
type: "POST",
url: "@Url.Action("FormSubmit","Home")",
data: data,
dataType: "json",
async: true,
contentType: "application/json",
processData: true,
success: function(result) { },
error: function(result) { }
});
控制器部分
[HttpPost]
public ActionResult FormSubmit(string input1, string input2)
{
var httpContext= HttpContext;
var response = Response;
var request = Request;
throw new NotImplementedException();
}
您可以像这样使用控制器:
[HttpPost]
public ActionResult SomeAction(string data)
{
List<YOUR_MODEL_CLASS> payloadObj = Newtonsoft.Json.JsonConvert.DeserializeObject<List<YOUR_MODEL_CLASS>>(data)(modelData);
// process your data
}
找到答案
我只需要阅读 post Payload
这是代码
[HttpPost]
public ActionResult FormSubmit()
{
Request.InputStream.Position = 0;
var reqMemStream = new MemoryStream(HttpContext.Request.BinaryRead(HttpContext.Request.ContentLength));
string reqString = Encoding.ASCII.GetString(reqMemStream.ToArray());
throw new NotImplementedException();
}
内容类型的结果:“application/x-www-form-urlencoded” 存储在 Request.Form 中 Asp MVC.
但是 "application/json" 我找不到商店位置
这是我使用的代码:
ajax部分
// reading form data
var form = $("form")[0];
var formData = new FormData(form);
var object = {};
formData.forEach(function(value, key){
object[key] = value;
});
var data = JSON.stringify(object);
// ajax part
// POST application/json; charset=utf-8
$.ajax({
type: "POST",
url: "@Url.Action("FormSubmit","Home")",
data: data,
dataType: "json",
async: true,
contentType: "application/json",
processData: true,
success: function(result) { },
error: function(result) { }
});
控制器部分
[HttpPost]
public ActionResult FormSubmit(string input1, string input2)
{
var httpContext= HttpContext;
var response = Response;
var request = Request;
throw new NotImplementedException();
}
您可以像这样使用控制器:
[HttpPost]
public ActionResult SomeAction(string data)
{
List<YOUR_MODEL_CLASS> payloadObj = Newtonsoft.Json.JsonConvert.DeserializeObject<List<YOUR_MODEL_CLASS>>(data)(modelData);
// process your data
}
找到答案 我只需要阅读 post Payload
这是代码
[HttpPost]
public ActionResult FormSubmit()
{
Request.InputStream.Position = 0;
var reqMemStream = new MemoryStream(HttpContext.Request.BinaryRead(HttpContext.Request.ContentLength));
string reqString = Encoding.ASCII.GetString(reqMemStream.ToArray());
throw new NotImplementedException();
}