有没有办法改变这个字典的输出？

Question

更改我的词典，这是初始代码：

bow=[[i for i in all_docs[j] if i not in stopwords] for j in range(n_docs)]
bow=list(filter(None,bow))
bow

这里是弓输出：

[['lunar',
  'satellite',
  'needs'],
['glad',
  'see',
  'griffin'] ]

worddict_two = [ (i,key) for i,key in enumerate(bow)]
worddict_two

来自这个输出：

 [(0,
  ['lunar',
   'satellite',
   'needs']),
  (1,
  ['glad',
   'see',
   'griffin'])

到此输出：

 [(0,'lunar satellite needs'),
  (1,'glad see griffin') ) ]

Answer 1

你可以这样做：

bow = [
        ['lunar','satellite','needs'],
        ['glad','see','griffin']
      ]

res = [(i,*key) for i,key in enumerate(bow)]

print(res)

Answer 2

worddict_two = [ (i, " ".join(key)) for i,key in enumerate(bow)]

这行得通。使用 join 将元组中的所有项目连接成一个字符串，以 space 作为分隔符

Answer 3

您可以像这样用空格加入列表

worddict_two = [ (i,' '.join(key)) for i,key in enumerate(bow)]

Answer 4

试试这个：

word_three = [(item[0], ', '.join(word for word in item[1])) for item in worddict_two]

Is there a way to change this dictionary output?