如何使用 Jq linux 将 json 数据拼接成单行

Question

我有一个 json 流，我想用 jq ( Linux )

将输出变成单行

由此

{
  "Icao": "800B0A",
  "Alt": 15375,
  "GAlt": 15278,
  "AltT": 0,
  "Lat": 10.579605,
  "Long": 76.506561,
  "Mlat": false,
  "Spd": 334.5,
  "Trak": 26.3,
  "Vsi": 832
}
{
  "Icao": "800463",
  "Alt": 3575,
  "GAlt": 3445,
  "AltT": 0,
  "Lat": 40.626663,
  "Long": -74.261963,
  "Mlat": false,
  "Spd": 274.4,
  "Trak": 316.2,
  "Vsi": 1472
}

对此

{"Icao":"A379CD","Alt":32025,"GAlt":32114,"InHg":30.0088577,"AltT":0,"Lat":38.335918,"Long":-104.720284,"Mlat":false,"Spd":403.0,"Trak":240.0,"Vsi":64},{"Icao":"345042","Alt":22850,"GAlt":22782,"InHg":29.8523617,"AltT":0,"Lat":39.655243,"Long":-8.845612,"Mlat":false,"Spd":308.5,"Trak":212.6,"Vsi":-1216},{"Icao":"40753D","Alt":37000,"GAlt":37050,"InHg":29.9704723,"AltT":0,"Lat":41.940674,"Long":-8.029816,"Mlat":false,"Spd":468.4,"Trak":190.2,"Vsi":-64},

希望有人能给出解决方案。

Answer 1

--compact-output（或-c）选项将在一行中打印每个对象，而--join-output（或-j）选项将省略换行符对象之间。

jq -cj .

{"Icao":"800B0A","Alt":15375,"GAlt":15278,"AltT":0,"Lat":10.579605,"Long":76.506561,"Mlat":false,"Spd":334.5,"Trak":26.3,"Vsi":832}{"Icao":"800463","Alt":3575,"GAlt":3445,"AltT":0,"Lat":40.626663,"Long":-74.261963,"Mlat":false,"Spd":274.4,"Trak":316.2,"Vsi":1472}

请注意，虽然这是有效的 JSON，但您想要的输出不是。它在对象之后有逗号。如果您真的需要它们，您可以使用 --raw-output（或 -r）选项打印逗号之类的文字字符串：

jq -cjr '.,","'

{"Icao":"800B0A","Alt":15375,"GAlt":15278,"AltT":0,"Lat":10.579605,"Long":76.506561,"Mlat":false,"Spd":334.5,"Trak":26.3,"Vsi":832},{"Icao":"800463","Alt":3575,"GAlt":3445,"AltT":0,"Lat":40.626663,"Long":-74.261963,"Mlat":false,"Spd":274.4,"Trak":316.2,"Vsi":1472},

如何使用 Jq linux 将 json 数据拼接成单行

How to Stitch json data into single line with Jq linux

linux

bash

json

jq

由此

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