计算 2 个日期之间的 INCLUDING 周数

Question

我需要计算 INCLUDING 周数（即使下周只有 1 天（周从星期一开始，在星期日结束), 也算作一周) 两个日期之间。

如果我使用常规的 datediff，两者的输出都是 2。

SELECT datediff(ww, '2022-03-01','2022-03-13')
SELECT datediff(ww, '2022-03-14','2022-03-31')

但我需要获得第 2 周和第 3 周：

From Date	To Date	Expected
2022-03-01	2022-03-13	falls in 2 weeks (02/28/2022 - 03/06/2022 and 03/07/2022 - 03/13/2022)
2022-03-14	2022-03-31	falls in 3 weeks (03/14/2022 - 03/20/2022, 03/21/2022 - 03/27/2022 and 03/28/2022 - 04/03/2022)

Answer 1

这是一个解决方案。注意 SQL 服务器将星期日作为一周的第一天。如果我们希望将星期一算作一周的第一天，我们必须从我们的日期中删除一天，如第二个查询。

CREATE TABLE dates (
From_Date date,   
To_Date   date);
INSERT INTO dates VALUES
('2022-03-01','2022-03-13'),  
('2022-03-14','2022-03-31');

SELECT
  From_Date ,
  DATENAME(ww, From_Date) FromWeek,
  To_Date,
  DATENAME(ww, To_Date) ToWeek,
  1 + CAST( DATENAME(ww, To_Date) AS INT)
    - CAST( DATENAME(ww, From_Date) AS INT) WeekDiff
FROM dates;

From_Date  | FromWeek | To_Date    | ToWeek | WeekDiff
:--------- | :------- | :--------- | :----- | -------:
2022-03-01 | 10       | 2022-03-13 | 12     |        3
2022-03-14 | 12       | 2022-03-31 | 14     |        3

SELECT
  From_Date ,
  DATENAME(ww, From_Date) FromWeek,
  To_Date,
  DATENAME(ww, To_Date) ToWeek,
  1 + CAST( DATENAME(ww, DATEADD(day, -1, To_Date)) AS INT)
    - CAST( DATENAME(ww, DATEADD(day, -1, From_Date)) AS INT) WeekDiff
FROM dates;

From_Date  | FromWeek | To_Date    | ToWeek | WeekDiff
:--------- | :------- | :--------- | :----- | -------:
2022-03-01 | 10       | 2022-03-13 | 12     |        2
2022-03-14 | 12       | 2022-03-31 | 14     |        3

db<>fiddle here

计算 2 个日期之间的 INCLUDING 周数

Calculate Number of INCLUDING Weeks between 2 dates

sql

sql-server

date