作为子查询一部分的 SQL 列的总计 运行

Running total for SQL column that is part of subquery

这里有很多帖子描述了如何进行 运行 总计,但我遇到的情况是 运行 总计需要是使用子查询计算的列的总计(这意味着我当前的 ORDER BY 导致查询失败)

我有一个 table 显示每个时间段的金额,如下所示:

TimePeriod   Amount
2022-03-31   396
2022-03-31   16
2022-03-31   84
2021-12-31   842
2021-12-31   57
2021-09-30   652
2021-09-30   25
2021-09-30   173

在我的查询中,我需要找到每个时间段占总数的百分比。我所做的是:

SELECT 
    TimePeriod,
    SUM(Amount) AS 'Total Per Period', 
    CAST( ROUND( SUM(Amount)/(SELECT SUM(Amount) FROM MyDatabase.MyTable),3) AS DECIMAL(12,3)) AS 'Percentage of Total'
FROM
    MyDatabase.MyTable
GROUP BY
    TimePeriod
ORDER BY
    TimePeriod DESC

这给了我一个正确的输出,像这样:

TimePeriod   Total per Period   Percentage of total
2022-03-31   496                0.221
2021-12-31   899                0.400
2021-09-30   850                0.379

我想要做的是在 'Percentage of total' 列中添加一个 运行 总数,例如:

TimePeriod   Total per Period   Percentage of total   Running total percentage
2022-03-31   496                0.221                 0.221
2021-12-31   899                0.400                 0.621
2021-09-30   850                0.379                 1.000

我试图做的是首先将它添加到第一个 SELECT 子句中,但这不起作用,因为它是一个只存在于我的查询中的列。然后我尝试对 select 做一个 select,像这样:

SELECT
    TimePeriod,
    'Total Per Period',
    'Percentage of Total',
    SUM('Percentage of Total') OVER (ORDER BY TimePeriod)
FROM
    (SELECT 
        TimePeriod,
        SUM(Amount) AS 'Total Per Period', 
        CAST( ROUND( SUM(Amount)/(SELECT SUM(Amount) FROM MyDatabase.MyTable),3) AS DECIMAL(12,3)) AS 'Percentage of Total'
    FROM
        MyDatabase.MyTable
    GROUP BY
        TimePeriod
    ORDER BY
        TimePeriod DESC)

这会抛出错误,指出子查询中不允许使用最后一个 ORDER BY。相反,删除 ORDER BY 表示语法不正确。我猜问题是我有一个引用子查询结果的子查询,但我不确定如何解决这个问题。我的查询中似乎缺少什么?

您可能需要使用[]来包含列名而不是',这意味着字符串值,我们还需要给子查询一个别名。

SELECT
    TimePeriod,
    [Total Per Period],
    [Percentage of Total],
    SUM([Percentage of Total]) OVER (ORDER BY TimePeriod)
FROM
    (SELECT 
        TimePeriod,
        SUM(Amount) AS 'Total Per Period', 
        CAST( ROUND( SUM(Amount)/(SELECT SUM(Amount) FROM MyDatabase.MyTable),3) AS DECIMAL(12,3)) AS 'Percentage of Total'
    FROM
        MyDatabase.MyTable
    GROUP BY
        TimePeriod) t1
ORDER BY
    TimePeriod DESC

您有一些语法错误,还有一些需要改进的地方:

  • 正如另一个答案中提到的,派生的 table 需要一个别名
  • 如有必要,请使用 [] 引用列名(最好一开始就不要使用此类列名)。
  • 您不能在派生的 table 或子查询中包含 ORDER BY,这样做也没有意义。
  • 您可以用 SUM(SUM) OVER () window 函数替换 SELECT SUM 子查询。
  • 如果 TimePeriod 可能有重复,运行 总计 window 函数必须有 ROWS UNBOUNDED PRECEDING。它也更快。
  • 因为您是按 TimePeriod DESC 排序的,所以 运行 总计的顺序与主 ORDER BY 相同但使用 ROWS BETWEEN CURRENT ROW AND UNBOUNDED FOLLOWING 可能会更快得出相同的结果。好处是查询计划中少了一种排序。
SELECT
    TimePeriod,
    [Total Per Period],
    [Percentage of Total],
    SUM([Percentage of Total]) OVER (ORDER BY TimePeriod DESC ROWS BETWEEN CURRENT ROW AND UNBOUNDED FOLLOWING)
FROM
    (SELECT 
        TimePeriod,
        SUM(Amount) AS [Total Per Period],
        CAST( ROUND( SUM(Amount) / SUM(SUM(Amount)) OVER () , 3) AS DECIMAL(12,3)) AS [Percentage of Total]
    FROM
        MyDatabase.MyTable
    GROUP BY
        TimePeriod
) t
ORDER BY
    TimePeriod DESC;

进一步的改进是将整个事情合并为一个级别:

SELECT
    TimePeriod,
    SUM(Amount) AS [Total Per Period],
    CAST( ROUND(
            SUM(Amount) /
            SUM(SUM(Amount)) OVER ()
          , 3) AS DECIMAL(12,3)) AS [Percentage of Total],
    CAST( ROUND(
            SUM(SUM(Amount)) OVER (ORDER BY TimePeriod DESC ROWS BETWEEN CURRENT ROW AND UNBOUNDED FOLLOWING) /
            SUM(SUM(Amount)) OVER ()
          , 3) AS DECIMAL(12,3))
FROM
    MyDatabase.MyTable
GROUP BY
    TimePeriod
ORDER BY
    TimePeriod DESC;

请注意,由于四舍五入,结果可能略有不同。

SQL Fiddle

这是我对你的问题的解决方案。我用Oracle解决了。

with flo as (
    select
      timeperiod, 
      sum(amount) as amount,
      cast((sum(amount) / (select sum(amount) from da ))as decimal(10,6)) *100.0 as percent_of_total
    from  yourtable
    group by timeperiod
)
select
  timeperiod,
  amount,
  percent_of_total,
  sum(percent_of_total) over (order by timeperiod desc ) as running
from flo;