希望获得为 oracle sql 开发人员输出构建的查询

Question

现有table

输出查询应该呈现这个

Answer 1

使用GROUP BY并取每列的MAX：

SELECT event,
       MAX(numericval) AS quantity,
       MAX(details) AS status
FROM   table_name
GROUP BY event

其中，对于示例数据：

CREATE TABLE table_name (event, elements, numericval, details) AS
SELECT 1, 'quality', 5, NULL FROM DUAL UNION ALL
SELECT 1, 'status', NULL, 'yes' FROM DUAL UNION ALL
SELECT 2, 'quality', 10, NULL FROM DUAL UNION ALL
SELECT 2, 'status', NULL, 'no' FROM DUAL UNION ALL
SELECT 3, 'quality', 15, NULL FROM DUAL UNION ALL
SELECT 3, 'status', NULL, 'yes' FROM DUAL;

输出：

EVENT QUANTITY STATUS

1 5 yes

2 10 no

3 15 yes

对于您的更新，您可以使用条件聚合：

SELECT event,
       MAX(CASE elements WHEN 'quality' THEN numericval END) AS quantity,
       MAX(CASE elements WHEN 'status' THEN details END) AS status,
       MAX(CASE elements WHEN 'Lot' THEN numericval END) AS lot
FROM   table_name
GROUP BY event

其中更新数据：

CREATE TABLE table_name (event, elements, numericval, details) AS
SELECT 1, 'quality', 5, NULL FROM DUAL UNION ALL
SELECT 1, 'status', NULL, 'yes' FROM DUAL UNION ALL
select 1 , 'Lot',1,null from dual union all
SELECT 2, 'quality', 10, NULL FROM DUAL UNION ALL
SELECT 2, 'status', NULL, 'no' FROM DUAL UNION ALL
select 2 , 'Lot',3,null from dual union all
SELECT 3, 'quality', 15, NULL FROM DUAL UNION ALL
SELECT 3, 'status', NULL, 'yes' FROM DUAL union all
select 3, 'Lot', 4,null from dual;

输出：

EVENT QUANTITY STATUS LOT

1 5 yes 1

2 10 no 3

3 15 yes 4

db<>fiddle here

希望获得为 oracle sql 开发人员输出构建的查询

looking to get a query constructed out for oracle sql developer output

sql

oracle

group-by