不同的数字年份 -Codewars Challenge-

Question

我在解决代码战挑战时陷入了死循环。任务是从给定的输入（如 1987 年）中找到下一个只有不同数字的更大整数。在那种情况下，它将是 2013，因为 1988、1998、2000 等没有 4 个不同的数字。我想用一个对象来解决这个任务，看看 Object.keys(obj) 的长度在哪里等于 4.

这是我的尝试

function distinctDigitYear(year) {
  
  let obj = {}
  let count = 1
  let yearCounter = year + count
  
  while (Object.keys(obj).length !==4) {
    obj = {}
    yearCounter.toString().split('').forEach(el=> {
      if(!Object.keys(obj).includes(el)){
        obj[el] = 1
      } else {
        obj[el] +=1
      }
    }
    )
   
      count++
  }
  return yearCounter + 1
}

distinctDigitYear(2000)

感谢阅读！

Answer 1

详情见下方示例

// Pass a 4 digit year -- 1987
function distinctDigitYear(year) {
  ++year; // Increment -- 1988
  /*
  Convert year number into a String. Spread the String into 4 
  separate characters with the spread operator ... then convert an 
  Array into a Set eliminates any duplicates, then convert it back to an Array.
  */
  let yyyy = [...new Set([...year.toString()])];
  // If there are no dupes, yyyy will be 4 characters
  if (yyyy.length === 4) {
    /*
    join() the array into a String and return it
    */
    return yyyy.join('');
  }
  /*
  If the lenght of yyyy is less than 4
  recursively call dDY() passing next year through.
  */
  return distinctDigitYear(year);
};

console.log(distinctDigitYear(1987));
console.log(distinctDigitYear(2020));
console.log(distinctDigitYear(1910));

不同的数字年份 -Codewars Challenge-

Distinct Digit Year -Codewars Challenge-

javascript

object

while-loop