为什么这个 "count" 函数不起作用？ (PHP/MYSQL)

Question

我有一个无法运行的 php/mysql 脚本！我需要找出字符串中确实存在多少行，我必须从 "boolean full text" 函数中计算。

这是不起作用的代码：

$resuslt=mysql_query("SELECT COUNT(homeid) 
                       FROM notes 
                       WHERE MATCH(title, text, tags) AGAINST('+$searchstring*' IN BOOLEAN MODE) AS accurate 
                       FROM notes 
                       WHERE MATCH(title, text, tags) AGAINST ('+$searchstring*' IN BOOLEAN MODE)");

我该怎么办？

Answer 1

这是你想要的吗？

SELECT COUNT(homeid) 
FROM notes 
WHERE MATCH(title, text, tags) AGAINST('+$searchstring*' IN BOOLEAN MODE) > 0;

如果 homeid 可以重复，您可能真的想要 count(distinct homeid)。

Answer 2

这应该是子选择吗？如果不是，你有两个发件人：

"SELECT COUNT(homeid) 
                       FROM notes 
                       WHERE MATCH(title, text, tags) AGAINST('+$searchstring*' IN BOOLEAN MODE) AS accurate 
                       FROM notes 
                       WHERE MATCH(title, text, tags) AGAINST ('+$searchstring*' IN BOOLEAN MODE)");

你可以试试这个：

SELECT (SELECT COUNT(homeid) 
                           FROM notes 
                           WHERE MATCH(title, text, tags) AGAINST('+$searchstring*' IN BOOLEAN MODE)) AS accurate
                           FROM notes 
                           WHERE MATCH(title, text, tags) AGAINST ('+$searchstring*' IN BOOLEAN MODE)

为什么这个 "count" 函数不起作用？ (PHP/MYSQL)

Why does this "count" function not work? (PHP/MYSQL)

php

mysql

count

boolean

full-text-search