根据另一列值将一列值拆分为多列

Question

能否请您帮我编写 select 查询以获得下图中的预期输出。我想要的是根据其 UOM 列值 ZF2、ZF1 和 ZF3 分别将 UPC 列值拆分为三列（Bottle UPC、Pack UPC、Case UPC）。

如有任何帮助，我们将不胜感激。谢谢！

Answer 1

您可以使用三个查询来分隔列并使用 UNION ALL 将它们连接起来。然后我们使用 max 只保留我们想要的那个。
我知道这与您显示的格式不完全相同，但它确实包含所有信息而没有重复。

Select
  Material_id,
  UOM,
  Max(Bottle) as Bottle_UPC, 
  Max(Pack) as Pack_UPC, 
  Max(Case) as Case_UPC
From 
(
Select
  Material_id,
  UOM,
  UPC as Bottle, 
  '' as Pack, 
  '' as Case
From table_name
Where UOM = 'ZF1'
   Union all
Select
  Material_id,
  UOM,
  '' , 
  UPC , 
  '' 
From table_name
Where UOM = 'ZF2'
   Union all
Select
  Material_id,
  UOM,
  '' , 
  '' , 
  UPC 
From table_name
Where UOM = 'ZF3'
)
Group by
  Material_id,
  UOM,

Answer 2

这是获得所需准确结果的一种方法，但令人困惑的是，为什么您希望所有三行都返回您已经仅转置到第一行的值...

;WITH cte AS 
(
  SELECT *, rn = ROW_NUMBER() OVER (PARTITION BY Material_ID ORDER BY UOM),
    bupc = CASE WHEN UOM = 'ZF2' THEN UPC END,
    pupc = CASE WHEN UOM = 'ZF1' THEN UPC END,
    cupc = CASE WHEN UOM = 'ZF3' THEN UPC END
  FROM dbo.SomeTableName AS s
),
agg AS 
(
  SELECT Material_ID, 
    bupc = MAX(bupc), 
    pupc = MAX(pupc), 
    cupc = MAX(cupc)
  FROM cte GROUP BY Material_ID
)
SELECT cte.Material_ID, cte.UOM, 
    [Bottle UPC] = COALESCE(agg.bupc, ''),
    [Pack UPC]   = COALESCE(agg.pupc, ''),
    [Case UPC]   = COALESCE(agg.cupc, '')
  FROM cte
  LEFT OUTER JOIN agg ON agg.Material_ID = cte.Material_ID
  AND cte.rn = 1;

示例db<>fiddle

根据另一列值将一列值拆分为多列

split one column values into multiple column based another column value

sql

sql-server-2012