哄骗 QUERY 接受数据范围的文本字符串？

Question

我有一个从多个 sheet 中提取数据的查询语句，它工作正常：

=QUERY({'A Physical Science'!A2:L; 'B Physical Science'!A2:L; 'E Physical Science'!A2:L; 'F Physical Science'!A2:L; 'G Physical Science'!A2:L},"select Col11 where Col6 is not null",0)

当我尝试为数据范围创建动态源时，它不再有效。我成功创建了一个与原始数据范围完全匹配的文本字符串公式

{'A Physical Science'!A2:L; 'B Physical Science'!A2:L; 'E Physical Science'!A2:L; 'F Physical Science'!A2:L; 'G Physical Science'!A2:L}

但无论我如何调用相邻 QUERY 语句中的数据范围，它只是 returns 文本字符串。 INDEX, ARRAYFORMULA, INDIRECT，大括号，没有什么使数据范围文本字符串栩栩如生。

@Ruben，我将我的旧函数添加到您的脚本中以实现动态，并在 google sheet 打开时将其触发到运行。只是检查是否有更优雅的方法来完成此操作？

function RangeArray() {
const skiplast = 5; //last 5 sheets need not be arrayed
var data = ""; //initialize string that will be the data range
var sheets = SpreadsheetApp.getActiveSpreadsheet().getSheets();
for (var i=0 ; i<sheets.length - skiplast ; i++) {
  data = data + "'"+ [ sheets[i].getName() ] + "'!A2:Z" ; //append the sheet names to the data string, plus necessary bits for parsing
  if (i<sheets.length - skiplast -1) {data = data + ";"} //except for the last sheet, also append a semicolon
  else {}
}

const here = SpreadsheetApp.getActiveSpreadsheet().getRange('DO NOT EDIT!A1');
const formula = '{'+ data +'}'; // make an array out of the data string
here.setFormula(formula);
}

Answer 1

无法转换像

这样的单元格值

{'A Physical Science'!A2:L; 'B Physical Science'!A2:L; 'E Physical Science'!A2:L; 'F Physical Science'!A2:L; 'G Physical Science'!A2:L}

使用 Google Sheets built-in 函数进入 Google Sheets 数组，但可以使用 Google Apps 脚本，将此值用作其中一个的参数setFormula 方法，即：

function addArray(){
  const a1 = SpreadsheetApp.getActiveSpreadsheet().getRange('Sheet1!A1');
  const formula = `{'A Physical Science'!A2:L; 'B Physical Science'!A2:L; 'E Physical Science'!A2:L; 'F Physical Science'!A2:L; 'G Physical Science'!A2:L}`;
  a1.setFormula(formula);
}

哄骗 QUERY 接受数据范围的文本字符串？

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