如何创建一个正则表达式，为每个句子证明几个句子特定关键字的存在？

Question

我要扫的文字是：“你今天怎么来了？” （关键词是“为什么”“你”“来”“这里”“今天”）

我想构建一个正则表达式，它也可以扫描类似的问题，例如：

“今天是什么把你带到这里来的？” （关键词是“什么”、“带来”、“你”、“今天”）
“今天进来的原因是什么？” （关键词是“什么”“原因”“即将到来”“今天”）
“你今天早上来这里有什么原因吗？” （关键词是“是”“原因”，“这里”，“早上”）
你今天怎么来了？（关键词是“为什么”、“你”、“这里”、“今天”）？

所以是这样的：/keywords from first sentence | keywords from second sentence | keywords from third sentence | etc... /ig

并且如果上面的正则表达式为真（使用.test），那么用户就会alerted something.

我试过使用以下方法：/(?=.*\bwhat's\b)(?=.*\bbrought\b)(?=.*\byou\b)(?=.*\btoday\b)|(?=.*\bwhy\b)(?=.*\byou\b)(?=.*\bhere\b)(?=.*\btoday\b)/ig。所以问哪个问题都没有关系，因为不管怎样都会执行相同的功能（我只需要匹配的关键词！）

我想构建一个正则表达式，可以从所有这些短语中扫描关键词，然后，如果关键词匹配，就会执行一个函数。如果有人对 topics/readings 创建这样一个正则表达式有任何建议，那就太好了！

Answer 1

@PeterSeliger would you have any advice on where I can look to get started on creating such a solution? – sb2021

1/2 A working solution needs a regex for splitting a multiline string into an array of (line) strings. One also needs an array of arrays where each nested array holds the keywords of a line/sentence.

2/3 ... Then one wants to check for the array of new lines whether every single line matches the keyword criteria. The callback function, which has to return a boolean value, then needs to check whether every line related keyword is part of the currently processed line. And the callback function of this task will utilize a dynamically created regex ...

3/3 ... which uses the i flag in order to test the existence of a keyword in a case insensitive way (ignore case) ... because of one of the OP's use cases where one runs into comparing "What's" versus "what's"

const sampleMultilineData =
`What's brought you here today?
What is the reason for coming in today?
Is there a reason you are here this morning?
Why are you here today?`;

const listOfKeywordLists = [
  ["what's", "brought", "you", "today"],
  ["what", "reason", "coming", "today"],
  ["is", "reason", "here", "morning"],
  ["why", "you", "here", "today"],
];

const isEveryLineContainsAllOfItsKeywords = sampleMultilineData
  // create array of separte lines
  // from the multiline string data.
  .split(/\n/)
  // wheter every single line matches the keyword criteria.
  .every((line, lineIndex) =>

    // access the line related keyword list via `lineIndex`.
    listOfKeywordLists[lineIndex]
      // wheter a line contains every keyword
      // with word boundaries (`\b`) to the keyword
      // in a case insensitive (`i` flag) way.
      .every(keyword =>
        RegExp(`\b${ keyword }\b`, 'i').test(line)
      )

      // // works case sensitive, thus the result is `false`.
      //.every(keyword => line.includes(keyword))
  );

console.log({ isEveryLineContainsAllOfItsKeywords });

.as-console-wrapper { min-height: 100%!important; top: 0; }

如何创建一个正则表达式，为每个句子证明几个句子特定关键字的存在？

How to create a regular expression which for each sentence proves the existence of several sentence specific keywords?

javascript

regex

arrays

string

matching