不输出列表中的每个值

Question

当我打印结果时，它只为每个函数打印一个 True/False 值。对于 dict1 和 dict2，它应该重复 return 多个值。

当前结果是：

False
True
False

预期结果是：打印(fullCoverageClearance(dict1)) -> [False, False]

print(fullCoverageClearance(dict2)) -> [False, True, False, True]

print(fullCoverageClearance(dict3)) -> [False]

代码如下：

dict1 = {"JS" : {"Paid" : [200, 400, 500, 600]}, "SK" : {"Paid": [400, 1000, 1600]}}
dict2 = {"JS" : {"Paid" : [200, 400, 500, 600]}, "SK" : {"Paid": [1010, 2000]}, "MJ":{"Paid" : [5, 6, 7]}, "ZF" : {"Paid": [2660, 500]}}
dict3 = {"SK" : {"Paid" : [200, 400]}}


def fullCoverageClearance(dict1):
   total1 = [sum(dict1["JS"]["Paid"]), sum(dict3["SK"]["Paid"])]
   for i in total1:
        if i <= 3000:
            return 'False'
        else:
            return 'True'  
def fullCoverageClearance(dict2):
   total2 = [sum(dict2["JS"]["Paid"]), sum(dict2["SK"]["Paid"]), sum(dict2["MJ"]["Paid"]), sum(dict2["ZF"]["Paid"])]
   for i in total2:
        if i <= 3000:
            return 'False'
        else:
            return 'True'
def fullCoverageClearance(dict3):
    total3 = [sum(dict3["SK"]["Paid"])]
    for i in total3:
        if i <= 3000:
            return 'False'
        else:
            return 'True'

print(fullCoverageClearance(dict1))
print(fullCoverageClearance(dict2))
print(fullCoverageClearance(dict3))

Answer 1

阅读你的代码，它混淆了你试图完成的事情。也许这会让您走上正确的道路：

dict1 = {"JS" : {"Paid" : [200, 400, 500, 600]}, "SK" : {"Paid": [400, 1000, 1600]}}

def fullCoverageClearance(vals):
   totals = [sum(vals["JS"]["Paid"]), sum(vals["SK"]["Paid"])]
   print(totals)
   results = []
   
   for amt in totals:
        print(amt)
        if amt <= 3000:
            results.append(False)
        else:
            results.append(True) 
            
   return results
            

print(fullCoverageClearance(dict1))


# Output
# [1700, 3000]
# 1700
# 3000
# [False, False]

更好的方法是将 fullCoverageClearance() 概括为 re-usable

dict1 = {"JS" : {"Paid" : [200, 400, 500, 600]}, "SK" : {"Paid": [400, 1000, 1600]}}
dict2 = {"JS" : {"Paid" : [200, 400, 500, 600]}, "SK" : {"Paid": [1010, 2000]}, "MJ":{"Paid" : [5, 6, 7]}, "ZF" : {"Paid": [2660, 500]}}
dict3 = {"SK" : {"Paid" : [200, 400]}}

def getFullCoverageClearance(data):
   results = []
   
   for key, val in data.items():
      total = sum(val['Paid'])
      
      if total <= 3000:
         results.append(False)
      else:
         results.append(True) 
            
   return results
   
print(getFullCoverageClearance(dict1))
print(getFullCoverageClearance(dict2))
print(getFullCoverageClearance(dict3))

# Output
# [False, False]
# [False, True, False, True]
# [False]

Answer 2

如果我没看错问题，这就是你想要的，我没有更改条件，这意味着实际输出是这样的：

[False, False]
[False, True, False, True]
[False]

第一个输出为 false 和 false 的原因是第二个值恰好是 3000，它将条件评估为 true 输出 false

dict1 = {"JS" : {"Paid" : [200, 400, 500, 600]}, "SK" : {"Paid": [400, 1000, 1600]}}
dict2 = {"JS" : {"Paid" : [200, 400, 500, 600]}, "SK" : {"Paid": [1010, 2000]}, "MJ":{"Paid" : [5, 6, 7]}, "ZF" : {"Paid": [2660, 500]}}
dict3 = {"SK" : {"Paid" : [200, 400]}}

def fullCoverageClearance1(dict1):
   total1 = [sum(dict1["JS"]["Paid"]), sum(dict1["SK"]["Paid"])]
   results = []
   for i in total1:
        if i <= 3000:
            results.append(False)
        else:
            results.append(True)
   return results


def fullCoverageClearance2(dict2):
   total2 = [sum(dict2["JS"]["Paid"]), sum(dict2["SK"]["Paid"]), sum(dict2["MJ"]["Paid"]), sum(dict2["ZF"]["Paid"])]
   results = []
   for i in total2:
       if i <= 3000:
           results.append(False)
       else:
           results.append(True)
   return results


def fullCoverageClearance3(dict3):
    total3 = [sum(dict3["SK"]["Paid"])]
    results = []
    for i in total3:
        if i <= 3000:
            results.append(False)
        else:
            results.append(True)
    return results

print(fullCoverageClearance1(dict1))
print(fullCoverageClearance2(dict2))
print(fullCoverageClearance3(dict3))

如果您使用 return，整个函数将退出并处理仅输出一个值的下一个函数。

此外，您的函数名称重叠，覆盖了之前声明的函数。

def fullCoverageClearance(dict1):
   total1 = [sum(dict1["JS"]["Paid"]), sum(dict3["SK"]["Paid"])]
   for i in total1:
        if i <= 3000:
            return 'False'
        else:
            return 'True'

如果您查看变量 total1 第二个元素，您会发现有错别字。请务必仔细检查您的代码。

不输出列表中的每个值

Not outputting every value from list

python

dictionary

return

function

list