为什么在将对象作为参数传递时不调用我的自定义构造函数？

Question

我有以下代码：


struct Entity {
    Entity() {
        std::cout << "[Entity] constructed\n";
    }

    ~Entity() {
        std::cout << "[Entity] destructed\n";
    }

    void Operation(void) {
        std::cout << "[Entity] operation\n";
    }
};

void funcCpy(Entity ent) {
    ent.Operation();
}

int main() {
    Entity e1;

    funcCpy(e1);
}

这是输出：

[Entity] constructed
[Entity] operation
[Entity] destructed
[Entity] destructed

我希望我的函数使用自定义构造函数，所以输出如下所示：

[Entity] constructed
[Entity] operation
[Entity] constructed
[Entity] destructed
[Entity] destructed

为什么会这样？我怎样才能改用我的自定义构造函数？

谢谢:)

Answer 1

https://en.cppreference.com/w/cpp/language/copy_constructor

对象作为参数将调用class

的复制构造函数

为什么在将对象作为参数传递时不调用我的自定义构造函数？

Why my custom constructor is not called when an object is passed as a parameter?

c++

constructor

copy

class

function