如何为 android 房间数据库编写 SQLite 查询

Question

我的用户 class 长什么样

  @Parcelize
    @Entity(tableName = "user_table")
    data class User(
        @PrimaryKey(autoGenerate = true)
        val id: Int,
        var name: String,
        var highScore: String?,
        var activeUser: Boolean,
    ): Parcelable

我的 UserDao 是什么样子

@Dao
interface UserDao {


    @Insert(onConflict = OnConflictStrategy.IGNORE)
    suspend fun addUser(user: User)

    @Update
    suspend fun updateUser(user: User)

    @Delete
    suspend fun deleteUser(user: User)

    @Query("DELETE FROM user_table")
    suspend fun deleteAllUsers()

    @Query("SELECT * FROM user_table ORDER BY id ASC")
    fun readAllData(): LiveData<List<User>>

    @Query("UPDATE user_table SET activeUser = 0")
    fun updateAllActiveUsers()

    @Update
    fun updateActiveUser(user: User)

}

您好，我想知道如何编写一个查询，使 select 所有活跃用户都为真。所以只有 activeUser = 1

Answer 1

SELECT * FROM user_table WHERE activeUser = true

或者如果执行挂起函数并希望传递布尔值

SELECT * FROM user_table WHERE activeUser = :value
suspend fun getUsers(value: Boolean): T

如何为 android 房间数据库编写 SQLite 查询

How to write a SQLite query for android room database

android

kotlin

android-sqlite