如何在 javascript 中检索具有相同属性值的对象数组

Question

我有一个对象数组，如果属性 items 具有相同的值，return javascript

中的那个数组对象

在下面的列表中，检索在

中具有相同值的对象数组

items 属性在 javascript

注意：也是动态对象数组，项目值可能会有所不同，所以不能直接用值过滤

var list =[
  {id: 1, name: "dev", items: "sales", code: "IN"},
  {id: 2, name: "lena", items: "finance", code: "SG"}
  {id: 3, name: "lisa", items: "sales", code: "AU"},
  {id: 4, name: "mano", items: "marketing", code: "IN"}
]

Expected Result
 {id: 1, name: "dev", items: "sales", code: "IN"}
 {id: 3, name: "lisa", items: "sales", code: "AU"},


var result= list.reduce((m, o) => {
  const found= m.find(e => e.items === o.items);
  if(found){
   m.push(o);
   return m
  }
}, []);

Answer 1

使用 reduce 找出所有重复项会更麻烦。你可以使用闭包。

const list = [
  { id: 1, name: "dev", items: "sales", code: "IN" },
  { id: 2, name: "lena", items: "finance", code: "SG" },
  { id: 3, name: "lisa", items: "sales", code: "AU" },
  { id: 4, name: "mano", items: "marketing", code: "IN" },
  { id: 5, name: "lisa", items: "gul gul", code: "AU" },
  { id: 6, name: "anthony", items: "some", code: "AU" },
  { id: 7, name: "mark", items: "gul gul", code: "AU" }
];

const findByItems = (eq) => (arr) => arr.filter(
  (x, i) => arr.find((y, j) => i !== j && eq(x, y))
)

const duplicatedItems = findByItems((a, b) => a.items === b.items);


console.log(duplicatedItems(list))

Answer 2

我个人会根据 items 值对输入中的项目进行分组，然后提取最长的一组（在您的示例中，财务和营销将有一个项目只有销售会有两个）：

var list = [
  {id: 1, name: "dev", items: "sales", code: "IN"},
  {id: 2, name: "lena", items: "finance", code: "SG"},
  {id: 3, name: "lisa", items: "sales", code: "AU"},
  {id: 4, name: "mano", items: "marketing", code: "IN"}
]

const map = {}
for (let item of list) {
  if (map[item.items]) {
    map[item.items].push(item);
  } else {
    map[item.items] = [item]
  }
}

let maxLength = 0, result;
for (let key in map) {
  if (map[key].length > maxLength) {
    maxLength = map[key].length
    result = map[key]
  }
}

console.log(result)

这将 return

[
  { id: 1, name: 'dev', items: 'sales', code: 'IN' },
  { id: 3, name: 'lisa', items: 'sales', code: 'AU' }
]

如您所料。

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