Laravel 模型:启动特征和模型
Laravel Model: boot on trait and model
我有一些 Laravel 模型使用调用模型引导方法的下一个特征:
<?php
namespace App\Traits;
use Illuminate\Support\Str;
trait Uuids
{
/**
* Boot function from Laravel.
*/
protected static function boot()
{
parent::boot();
static::creating(function ($model) {
if (empty($model->{$model->getKeyName()})) {
$model->{$model->getKeyName()} = Str::uuid()->toString();
if ($model->consecutive) {
$model->consecutive = $model->max("consecutive") + 1;
}
}
});
}
/**
* Get the value indicating whether the IDs are incrementing.
*
* @return bool
*/
public function getIncrementing()
{
return false;
}
/**
* Get the auto-incrementing key type.
*
* @return string
*/
public function getKeyType()
{
return "string";
}
}
但是在其中一个模型上,我有一个 consecutive
列,我需要自动增加它,我是通过模型中的引导功能来做到这一点的:
<?php
namespace App\Models;
use Illuminate\Database\Eloquent\Factories\HasFactory;
use Illuminate\Database\Eloquent\Model;
use Illuminate\Database\Eloquent\SoftDeletes;
class Order extends Model
{
use HasFactory, Uuids;
public static function boot()
{
parent::boot();
self::creating(function ($model) {
$model->consecutive = $model->max("consecutive") + 1;
});
}
}
问题是只有特征的 boot()
被调用了。是否有另一种方法来填充我的模型的 consecutive
列或在两个文件上调用 boot()
方法?
Uuids
中的 boot
函数将不会被触发,为了解决这个问题,Laravel 中有一个很棒的隐藏功能,它说明如果你的特征中的函数名称是bootYourTraitName
它会被引导模型功能触发,就像这样
<?php
namespace App\Traits;
use Illuminate\Support\Str;
trait Uuids
{
/**
* Boot function from Laravel.
*/
protected static function bootUuids()
{
static::creating(function ($model) {
if (empty($model->{$model->getKeyName()})) {
$model->{$model->getKeyName()} = Str::uuid()->toString();
if ($model->consecutive) {
$model->consecutive = $model->max("consecutive") + 1;
}
}
});
}
/**
* Get the value indicating whether the IDs are incrementing.
*
* @return bool
*/
public function getIncrementing()
{
return false;
}
/**
* Get the auto-incrementing key type.
*
* @return string
*/
public function getKeyType()
{
return "string";
}
}
我有一些 Laravel 模型使用调用模型引导方法的下一个特征:
<?php
namespace App\Traits;
use Illuminate\Support\Str;
trait Uuids
{
/**
* Boot function from Laravel.
*/
protected static function boot()
{
parent::boot();
static::creating(function ($model) {
if (empty($model->{$model->getKeyName()})) {
$model->{$model->getKeyName()} = Str::uuid()->toString();
if ($model->consecutive) {
$model->consecutive = $model->max("consecutive") + 1;
}
}
});
}
/**
* Get the value indicating whether the IDs are incrementing.
*
* @return bool
*/
public function getIncrementing()
{
return false;
}
/**
* Get the auto-incrementing key type.
*
* @return string
*/
public function getKeyType()
{
return "string";
}
}
但是在其中一个模型上,我有一个 consecutive
列,我需要自动增加它,我是通过模型中的引导功能来做到这一点的:
<?php
namespace App\Models;
use Illuminate\Database\Eloquent\Factories\HasFactory;
use Illuminate\Database\Eloquent\Model;
use Illuminate\Database\Eloquent\SoftDeletes;
class Order extends Model
{
use HasFactory, Uuids;
public static function boot()
{
parent::boot();
self::creating(function ($model) {
$model->consecutive = $model->max("consecutive") + 1;
});
}
}
问题是只有特征的 boot()
被调用了。是否有另一种方法来填充我的模型的 consecutive
列或在两个文件上调用 boot()
方法?
Uuids
中的 boot
函数将不会被触发,为了解决这个问题,Laravel 中有一个很棒的隐藏功能,它说明如果你的特征中的函数名称是bootYourTraitName
它会被引导模型功能触发,就像这样
<?php
namespace App\Traits;
use Illuminate\Support\Str;
trait Uuids
{
/**
* Boot function from Laravel.
*/
protected static function bootUuids()
{
static::creating(function ($model) {
if (empty($model->{$model->getKeyName()})) {
$model->{$model->getKeyName()} = Str::uuid()->toString();
if ($model->consecutive) {
$model->consecutive = $model->max("consecutive") + 1;
}
}
});
}
/**
* Get the value indicating whether the IDs are incrementing.
*
* @return bool
*/
public function getIncrementing()
{
return false;
}
/**
* Get the auto-incrementing key type.
*
* @return string
*/
public function getKeyType()
{
return "string";
}
}