javascript中字符串数组获取对象所有叶节点属性的函数

Question

请求您帮助在 javascript 中构建一个函数，以从给定的输入中获得提到的输出。

INPUT : 一个对象（可能是嵌套对象）

示例：

{

"消息":"字符串",

“数据 1”：{

    "Output1": {

        "leaf1": "abc",

        "Leaf2": "123"

    }

}

“数据2”：{

    "Output2": {

        "leaf3": "abc",

        "leaf4": "123"

    }

}

}

输出：字符串数组

示例： str= ["消息", "data1.Output1.leaf1", "data1.Output1.leaf2", "data2.Output2.leaf3","data2.Output2.leaf4"]

Answer 1

像这样它会起作用

const getBranches = (data, prefix=[]) => {
  if (typeof(data) !== 'object') {
    return prefix.join('.')
  }
  return Object.entries(data).flatMap(([k, v]) => getBranches(v, [...prefix, k]))

  }

  const data = {
    "message": "string",
    "data1": {
      "Output1": {
        "leaf1": "abc",
        "Leaf2": "123"
      }
    },
    "data2": {
      "Output2": {
        "leaf3": "abc",
        "leaf4": "123"
      }
    }
  }


console.log(getBranches(data))

第二个版本

const data = {
  "message": "string",
  "data1": {
    "Output1": {
      "leaf1": [{
        "b": {
          "c": "12"
        }
      }]
    }
  },
  "data2": {
    "Output2": {
      "leaf3": "abc",
      "leaf4": "123"
    }
  }
}
const getBranches = (data, prefix = []) => {
  if (typeof(data) !== 'object') {
    return prefix.join('.')
  }
  return Object.entries(data).flatMap(([k, v]) => Array.isArray(data) ? getBranches(v, [...prefix]) : getBranches(v, [...prefix, k]))
}

console.log(getBranches(data))

javascript中字符串数组获取对象所有叶节点属性的函数

A function to obtain all leaf node properties of an object in an array of string in javascript

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