将以 \\?\ 开头的设备路径转换为 Path

Question

我想在 java 程序中读取和写入数据到 HID 设备。

Windows 中的设备路径格式如下： \?\HID#VID_XXXX&PID_XXXX#...#{xxxxxxxx-xxxx-xxxx-xxxx-xxxxxxxxxxxx}。 \?\ 前缀是 special windows namespace.
我可以使用 RandomAccessFile 打开设备没有问题，因为构造函数需要 String.
但是，当我尝试将其转换为 Path 时，会发生这种情况：

Path.of("\\?\HID#VID_XXXX&PID_XXXX#...#{xxxxxxxx-xxxx-xxxx-xxxx-xxxxxxxxxxxx}");

Exception in thread "main" java.nio.file.InvalidPathException: Illegal character [?] in path at index 2: \?\HID#VID_XXXX&PID_XXXX#...#{xxxxxxxx-xxxx-xxxx-xxxx-xxxxxxxxxxxx}
    at java.base/sun.nio.fs.WindowsPathParser.nextSlash(WindowsPathParser.java:212)
    at java.base/sun.nio.fs.WindowsPathParser.parse(WindowsPathParser.java:111)
    at java.base/sun.nio.fs.WindowsPathParser.parse(WindowsPathParser.java:77)
    at java.base/sun.nio.fs.WindowsPath.parse(WindowsPath.java:92)
    at java.base/sun.nio.fs.WindowsFileSystem.getPath(WindowsFileSystem.java:232)
    at java.base/java.nio.file.Path.of(Path.java:147)
    at ...

因为我想使用 AsynchronousFileChannel class，我必须先将它转换为 Path。有办法吗？

Answer 1

用 \.\ 替换 \?\ 似乎可以解决问题：

String rawPath = "\\?\HID#VID_XXXX&PID_XXXX#...#{xxxxxxxx-xxxx-xxxx-xxxx-xxxxxxxxxxxx}"
var newPath = Path.of(rawPath.replace("\\?\", "\\.\");

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