加入两个数据集并计算不同的值

Question

所以我有一个我试图合并的两个数组的对象。

我的主要目标是从 dataOne 中获取唯一类型。然后我需要每种类型的总出现次数。然后，我需要知道每种类型的成功和失败总数。

然后我需要从 dataTwo 中包含每种类型的点击次数。

目前我有以下实现这一点的方法，尽管我确信它可以被整理。

const ob = {
  "dataOne": [
    {
      "type": "Type 1",
      "name": "failed"
    },
    {
      "type": "Type 1",
      "name": "success"
    },
    {
      "type": "Type 2",
      "name": "success"
    },
    {
      "type": "Type 3",
      "name": "success"
    },
  ],
  "dataTwo": [
    {
      "type": "Type 1",
      "name": "click",
    },
    {
      "type": "Type 2",
      "name": "click",
    },
    {
      "type": "Type 2",
      "name": "click",
    },
    {
      "type": "Type 1",
      "name": "click",
    },
    {
      "type": "Type 3",
      "name": "click",
    },
  ]
};

const dataOneReduced = ob.dataOne.reduce((acc, o) => {
  if (!acc[o.type]) {
    acc[o.type] = [
      {
        count: 0,
        success: 0,
        failed: 0,
        click: 0,
      },
    ];
  }

  acc[o.type][0]["count"] = (acc[o.type][0]["count"] || 0) + 1;
  acc[o.type][0][o.name] = acc[o.type][0][o.name] + 1;

  return acc;
}, {});

const result = ob.dataTwo.reduce((acc, o) => {
  acc[o.type][0][o.name] = acc[o.type][0][o.name] + 1;

  return acc;
}, dataOneReduced);

console.log(result);

我现在要做的是以百分比形式插入成功率。所以我需要输出像这样

{
  "Type 1": [
    {
      "count": 2,
      "success": 1,
      "failed": 1,
      "click": 2,
      "successPecentage": 50
    }
  ],
  "Type 2": [
    {
      "count": 1,
      "success": 1,
      "failed": 0,
      "click": 2,
      "successPecentage": 100
    }
  ],
  "Type 3": [
    {
      "count": 1,
      "success": 1,
      "failed": 0,
      "click": 1,
      "successPecentage": 100,
    }
  ]
}

我该如何实现？

谢谢

Answer 1

所需的 objective 可以通过添加一行来实现： acc[o.type][0].successPercentage = Math.round(acc[o.type][0].success / acc[o.type][0].count * 100); 如下片段所示

代码段

const ob = {
  "dataOne": [
    {
      "type": "Type 1",
      "name": "failed"
    },
    {
      "type": "Type 1",
      "name": "success"
    },
    {
      "type": "Type 2",
      "name": "success"
    },
    {
      "type": "Type 3",
      "name": "success"
    },
  ],
  "dataTwo": [
    {
      "type": "Type 1",
      "name": "click",
    },
    {
      "type": "Type 2",
      "name": "click",
    },
    {
      "type": "Type 2",
      "name": "click",
    },
    {
      "type": "Type 1",
      "name": "click",
    },
    {
      "type": "Type 3",
      "name": "click",
    },
  ]
};

const dataOneReduced = ob.dataOne.reduce((acc, o) => {
  if (!acc[o.type]) {
    acc[o.type] = [
      {
        count: 0,
        success: 0,
        failed: 0,
        click: 0,
      },
    ];
  }

  acc[o.type][0]["count"] = (acc[o.type][0]["count"] || 0) + 1;
  acc[o.type][0][o.name] = acc[o.type][0][o.name] + 1;

  return acc;
}, {});

const result = ob.dataTwo.reduce((acc, o) => {
  acc[o.type][0][o.name] = acc[o.type][0][o.name] + 1;
  acc[o.type][0].successPercentage = Math.round(acc[o.type][0].success / acc[o.type][0].count * 100);
  return acc;
}, dataOneReduced);

console.log(result);

Answer 2

选项 1

您可以再循环一次您的对象并插入百分比。这不是最好的解决方案performance-wise，但它更简单。

const ob = {
  "dataOne": [
    {
      "type": "Type 1",
      "name": "failed"
    },
    {
      "type": "Type 1",
      "name": "success"
    },
    {
      "type": "Type 2",
      "name": "success"
    },
    {
      "type": "Type 3",
      "name": "success"
    },
  ],
  "dataTwo": [
    {
      "type": "Type 1",
      "name": "click",
    },
    {
      "type": "Type 2",
      "name": "click",
    },
    {
      "type": "Type 2",
      "name": "click",
    },
    {
      "type": "Type 1",
      "name": "click",
    },
    {
      "type": "Type 3",
      "name": "click",
    },
  ]
};

const dataOneReduced = ob.dataOne.reduce((acc, o) => {
  if (!acc[o.type]) {
    acc[o.type] = [
      {
        count: 0,
        success: 0,
        failed: 0,
        click: 0,
      },
    ];
  }

  acc[o.type][0]["count"] = (acc[o.type][0]["count"] || 0) + 1;
  acc[o.type][0][o.name] = acc[o.type][0][o.name] + 1;

  return acc;
}, {});

const result = ob.dataTwo.reduce((acc, o) => {
  acc[o.type][0][o.name] = acc[o.type][0][o.name] + 1;

  return acc;
}, dataOneReduced);

for (const type of Object.keys(result)) {
  const obj = result[type][0];
  obj.successPercentage = obj.success / obj.count * 100;
}

console.log(result);

选项 2

您可以将计算直接插入 .reduce()，它会很好地工作，因为每次迭代只会覆盖值，并且只有最后一个正确的值会出现在输出中。

const ob = {
  "dataOne": [
    {
      "type": "Type 1",
      "name": "failed"
    },
    {
      "type": "Type 1",
      "name": "success"
    },
    {
      "type": "Type 2",
      "name": "success"
    },
    {
      "type": "Type 3",
      "name": "success"
    },
  ],
  "dataTwo": [
    {
      "type": "Type 1",
      "name": "click",
    },
    {
      "type": "Type 2",
      "name": "click",
    },
    {
      "type": "Type 2",
      "name": "click",
    },
    {
      "type": "Type 1",
      "name": "click",
    },
    {
      "type": "Type 3",
      "name": "click",
    },
  ]
};

const dataOneReduced = ob.dataOne.reduce((acc, o) => {
  if (!acc[o.type]) {
    acc[o.type] = [
      {
        count: 0,
        success: 0,
        failed: 0,
        click: 0,
      },
    ];
  }

  acc[o.type][0]["count"] = (acc[o.type][0]["count"] || 0) + 1;
  acc[o.type][0][o.name] = acc[o.type][0][o.name] + 1;
  acc[o.type][0].successPercentage = acc[o.type][0].success / acc[o.type][0].count * 100;

  return acc;
}, {});

const result = ob.dataTwo.reduce((acc, o) => {
  acc[o.type][0][o.name] = acc[o.type][0][o.name] + 1;

  return acc;
}, dataOneReduced);

console.log(result);

加入两个数据集并计算不同的值

Joining two data sets and calculating different values

javascript

ecmascript-6

选项 1

选项 2