TypeError: plot() missing 1 required positional argument: 'kind'

Question

我正在使用 plotly 在网络图形上处理 Kaggle tutorial。经过一些更新以获得与 chart_studio 兼容的代码后，我现在收到错误：

TypeError: plot() missing 1 required positional argument: 'kind'

我为尝试获取图表而输入的代码是：

import plotly.express as px
import pandas as pd
import networkx as nx
from plotly.offline import download_plotlyjs, init_notebook_mode, iplot
import plotly.graph_objs as go
import numpy as np

init_notebook_mode(connected=True)

#AT&T network data
network_df=pd.read_csv('network_data.csv')

#source_ip and destination_ip are of our interest here. so we isolate them. We then get the unique ip addresses for getting
#the total number of nodes. We do this by taking unique values in both columns and joining them together.

A = list(network_df["source_ip"].unique())
B = list(network_df["destination_ip"].unique())
node_list = set(A+B)

#Creating the Graph

G = nx.Graph()

#Graph api to create an empty graph. And the below cells we will create nodes and edges and add them to our graph
for i in node_list:
    G.add_node(i)

G.nodes()

pos = nx.spring_layout(G, k=0.5, iterations=50)

for n, p in pos.items():
    G.nodes[n]['pos'] = p

edge_trace = go.Scatter(
    x=[],
    y=[],
    line=dict(width=0.5,color='#888'),
    hoverinfo='none',
    mode='lines')

for edge in G.edges():
    x0, y0 = G.node[edge[0]]['pos']
    x1, y1 = G.node[edge[1]]['pos']
    edge_trace['x'] += tuple([x0, x1, None])
    edge_trace['y'] += tuple([y0, y1, None])

node_trace = go.Scatter(
    x=[],
    y=[],
    text=[],
    mode='markers',
    hoverinfo='text',
    marker=dict(
        showscale=True,
        colorscale='RdBu',
        reversescale=True,
        color=[],
        size=15,
        colorbar=dict(
            thickness=10,
            title='Node Connections',
            xanchor='left',
            titleside='right'
        ),
        line=dict(width=0)))

for node in G.nodes():
    x, y = G.nodes[node]['pos']
    node_trace['x'] += tuple([x])
    node_trace['y'] += tuple([y])

for node, adjacencies in enumerate(G.adjacency()):
    node_trace['marker']['color']+=tuple([len(adjacencies[1])])
    node_info = adjacencies[0] +' # of connections: '+str(len(adjacencies[1]))
    node_trace['text']+=tuple([node_info])

#Start plotting
fig = go.Figure(data=[edge_trace, node_trace],
             layout=go.Layout(
                title='<br>AT&T network connections',
                titlefont=dict(size=16),
                showlegend=False,
                hovermode='closest',
                margin=dict(b=20,l=5,r=5,t=40),
                annotations=[ dict(
                    text="No. of connections",
                    showarrow=False,
                    xref="paper", yref="paper") ],
                xaxis=dict(showgrid=False, zeroline=False, showticklabels=False),
                yaxis=dict(showgrid=False, zeroline=False, showticklabels=False)))

#the above code gave me an error because it wasn't set up for chart_studio

iplot(fig)
plotly.plot(fig)

from chart_studio.plotly import plot
from chart_studio import plotly
import plotly
import chart_studio

chart_studio.tools.set_credentials_file(username='anand0427', api_key='5Xd8TlYYqnpPY5pkdGll')

iplot(fig,"anand0427",filename="Network Graph.html")

iplot(fig)
plotly.plot(fig)

如有任何帮助，我们将不胜感激。

我环顾四周，试图找出 kind 的含义以及如何针对此图表调整它。

完整追溯：

---------------------------------------------------------------------------
TypeError                                 Traceback (most recent call last)
<ipython-input-40-e49e5cb9a1e3> in <module>()
      2 
      3 iplot(fig)
----> 4 plotly.plot(fig)

TypeError: plot() missing 1 required positional argument: 'kind'

Answer 1

问题出在您的代码和教程中使用的不明确的导入语句。

你有

from chart_studio import plotly
import plotly

表示定义了两次plotly，只剩下第二次定义。教程也有同样的问题，from plotly import plotly后跟[=13=].

所以当你调用 plotly.plot() 时，你并不是在调用 chart_studio.plotly.plot()，我相信这是你的意图，而是你调用了 plot() 中定义的函数17=]，其in-code documentation表示不打算直接调用。

除非您知道自己需要它，否则请删除行 import plotly，或将这两行导入行之一更改为 as <some other name>，这样您就可以引用 chart_studio.plotly 和以不同的、明确的名称为基础 plotly。

TypeError: plot() missing 1 required positional argument: 'kind'

TypeError: plot() missing 1 required positional argument: 'kind'

python

typeerror

plotly