Hive：不支持的子查询表达式 'extract_date'：仅允许作为顶级连词的子查询表达式

Question

我是 HIVE 的新手，我目前在 WSL2 上使用 HIVE 3.1.2，我正在尝试使用命令 在 HIVE CLI 上运行这个 SQL 脚本配置单元-f test2subquery.sql:

use mydb;

SELECT
    date_photo as extract_date, camping_code, 0 as nb_credit , 0 as nb_debit, SUM(s.nb_nuit_fid)
FROM

(

  SELECT
        extract_date as date_photo, camping_code, count(*) as nb_nuit_fid
  FROM
        extract_resa 
  WHERE
        extract_date = (select  CAST(y.extract_date as date) from app_params y)
  AND extract_date>= datein 
  AND extract_date< date_add(datein, nb_nuit_fid) 
  AND nb_nuit_fid > 0
  AND statres <> 'X'
  AND id_stay_to = 'NULL'  -- eliminer les TO
  AND idstay <> idstay_res -- seulement les residents reel
  AND client_id_grp <> -1
  GROUP BY
   extract_date , camping_code

  )e
GROUP BY
date_photo, camping_code

但我不断收到此错误：不支持的子查询表达式'extract_date'：仅允许作为顶级连词的子查询表达式 我尝试在子查询中使用别名，但我仍然遇到相同的错误。

use mydb;

SELECT
    s.extract_date, s.camping_code, 0 as nb_credit , 0 as nb_debit, SUM(s.nb_nuit_fid)
FROM

(

  SELECT
        r.extract_date, r.camping_code, count(*) as nb_nuit_fid
  FROM
        extract_resa r
  WHERE
        r.extract_date = (select  CAST(y.extract_date as date) from app_params y)
  AND r.extract_date>= r.datein 
  AND r.extract_date< date_add(r.datein, nb_nuit_fid) 
  AND nb_nuit_fid > 0
  AND r.statres <> 'X'
  AND r.id_stay_to = 'NULL'  -- eliminer les TO
  AND r.idstay <> r.idstay_res -- seulement les residents reel
  AND r.client_id_grp <> -1
  GROUP BY
   r.extract_date , r.camping_code

  )s
GROUP BY
date_photo, camping_code

同样让我感到困惑的是，在评论行 extract_date< date_add(datein, nb_nuit_fid) 时，像这样：

use mydb;

SELECT
    s.date_photo as extract_date, s.camping_code, 0 as nb_credit , 0 as nb_debit, SUM(s.nb_nuit_fid)
FROM

(

  SELECT
            extract_date as date_photo, camping_code, count(*) as nb_nuit_fid
  FROM
            extract_resa 
  WHERE
           extract_date <   (select cast(y.extract_date as date) from app_params y) 
  AND 
  extract_date >= datein 
  /* AND extract_date < date_add(datein, nb_nuit_fid) */
  AND nb_nuit_fid > 0
  AND statres <> 'X'
  AND id_stay_to = 'NULL'  -- eliminer les TO
  AND idstay <> idstay_res -- seulement les residents reel
  AND client_id_grp <> -1
  GROUP BY
     extract_date, camping_code
  )s
GROUP BY
date_photo, camping_code

脚本运行很顺利。请帮忙

Answer 1

将您的子查询子句转换为内连接。

use mydb;

SELECT
    s.extract_date, s.camping_code, 0 as nb_credit , 0 as nb_debit, SUM(s.nb_nuit_fid)
FROM

(

  SELECT
        r.extract_date, r.camping_code, count(*) as nb_nuit_fid
  FROM
        extract_resa r
  INNER JOIN (select  CAST(y.extract_date as date) ext_dt from app_params y) y ON  r.extract_date = y.ext_dt -- this inner join will work same as your filter in subquery
  WHERE 
      r.extract_date>= r.datein 
  AND r.extract_date< date_add(r.datein, nb_nuit_fid) 
  AND nb_nuit_fid > 0
  AND r.statres <> 'X'
  AND r.id_stay_to = 'NULL'  -- eliminer les TO
  AND r.idstay <> r.idstay_res -- seulement les residents reel
  AND r.client_id_grp <> -1
  GROUP BY
   r.extract_date , r.camping_code

  )s
GROUP BY
date_photo, camping_code

我不确定该行的评论效果如何。请告诉我结果。

Hive：不支持的子查询表达式 'extract_date'：仅允许作为顶级连词的子查询表达式

Hive: Unsupported SubQuery Expression 'extract_date': Only SubQuery expressions that are top level conjuncts are allowed

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