MongoDB 将对象元素合并到聚合中的另一个元素

Question

所以我现在有这个对象

{
  "notifications": [
    {
      "author": "5862184743205863247",
      "type": "friend",
      "value": "5862184743205863247",
      "avatar": "https://avatars.dicebear.com/api/avataaars/ZAZA.png",
      "id": "5861675623319076687",
      "createdAt": "2022-03-24T13:43:06.637Z",
      "status": "Hello! I just joined unchat!",
      "username": "ZAZA"
    }
  ]
}

如何将 username, status, createdAt, id 合并到 author 元素。所以结果是

 {
  "notifications": [
    {
      "author": {
        "avatar": "https://avatars.dicebear.com/api/avataaars/ZAZA.png",
        "id": "5861675623319076687",
        "createdAt": "2022-03-24T13:43:06.637Z",
        "status": "Hello! I just joined unchat!",
        "username": "ZAZA"
      },
      "type": "friend",
      "value": "5862184743205863247"
    }
  ]
}

这是我现在正在使用的代码，我使用查找来获取其他作者对象，例如用户名或 ID

https://sourceb.in/aUjZQ5DJU9

抱歉，我把它放在 sourcebin 中，因为它很长而且我不想让表格变得凌乱

Answer 1

db.collection.aggregate([
  {
    $set: {
      notifications: {
        $map: {
          input: "$notifications",
          as: "n",
          in: {
            author: {
              avatar: "$$n.avatar",
              id: "$$n.id",
              createdAt: "$$n.createdAt",
              status: "$$n.status",
              username: "$$n.username"
            },
            type: "$$n.type",
            value: "$$n.value"
          }
        }
      }
    }
  }
])

mongoplayground

MongoDB 将对象元素合并到聚合中的另一个元素

MongoDB merging an object element to another element from aggregate

typescript

mongodb

mongoose