如何通过 mysql 中的 id 排除每组中的最后一行？

Question

这 3 列是 employee_id、月份、薪水。如何排除每个 employee_id 组中的最后一行？

[1, 1, 20] 
[1, 2, 30] 
[1, 3, 40] 
[1, 4, 60] 
[1, 7, 90] 
[1, 8, 90]  #exclude

[2, 1, 20] 
[2, 2, 30] #exclude

[3, 2, 40] 
[3, 3, 60] 
[3, 4, 70] #exclude

我的查询添加了行号，但我该怎么办？

select 
id, month, salary, 
row_number()over(partition by id order by id) as ro #i tried this ,but how?


from employee 
order by id, month

Answer 1

您可以在行号中使用 order by month DESC，然后排除对应于该 ID 最近月份的 1。

select id, month, salary 
from (
select 
id, month, salary, 
row_number()over(partition by id order by month desc) as ro 
from employee ) e
where ro > 1
order by id, month;

Answer 2

对于 8.0 之前的版本，可以使用相关子查询来完成此操作。

select * From `table` t where not exists
(select id,max(`month`) mx from `table` group by id having t.id=id and t.`month`=mx) 
;

如何通过 mysql 中的 id 排除每组中的最后一行？

how to exclude last row in every group by id in mysql?

mysql

window

row-number