如何将字典中的每个值转换为单独的列表？

Question

所以我试图将 payload 中的值转换为单独的列表。 fruits 的第一个值，我试图将其放在 fruits 列表中，与 vegetables.

相同

main.py

import requests

headers = {
  'Content-Type': 'application/json'
}

list_of_fruits = ["orange", "banana", "mango"]
list_of_vegetables = ["squash", "brocoli", "aspharagus"]

payload = {
    "fruits": list_of_fruits
    "vegetables": list_of_vegetables
}

response = requests.post(f"127.1.1.1:9000/json", headers=headers, json=payload)

------------------------------------------------------------------------------------------

flask_api.py

from flask import Flask, request

@app.route('/post_json', methods=['POST'])
def process_json():
    content_type = request.headers.get('Content-Type')
    if (content_type == 'application/json'):
        
        fruits= [] 
        vegetables = []
         
        data = request.json
        for k, v in data.items(): #How can I convert the first list of values to the fruits list? and the same for vegetables?
            print(v) ---> ["orange", "banana", "mango"]["squash", "brocoli", "aspharagus"]
        
        return data
    else:
        return 'Content-Type not supported!'

#Output ---> ["orange", "banana", "mango"]["squash", "brocoli", "aspharagus"]

Answer 1

您需要从请求中读取数据。你的请求是这样的

{
   'fruits': ['list of fruits'],
   'vegetables': ['list of vegetables']

}

您正在使用 data = requests.json 读取 json 格式的请求数据，其格式与上述格式相同。

现在read/save列表中的数据，需要从data字典中读取数据并保存在列表中。

fruits = data.get('fruits', []) # [] in case no 'fruits' as key value in payload
vegetables = data.get('vegetables', [])

这里fruits和vegetables是您保存数据的列表。

如何将字典中的每个值转换为单独的列表？

How to convert each value in a dictionary to a separate list?

python

list

rest

for-loop

flask