Selenium chromedriver error: The AudioContext was not allowed to start. It must be resumed (or created) after a user gesture on the page

Question

我正在尝试访问此网站上的数据： https://vemcount.app/embed/widget/uOCRuLPangWo5fT?locale=en

到目前为止我的代码如下：

from bs4 import BeautifulSoup
from selenium import webdriver
from selenium.webdriver.chrome.options import Options
from selenium.webdriver.common.keys import Keys
from selenium.webdriver.support.ui import WebDriverWait
from selenium.common.exceptions import TimeoutException


def configure_driver():
    chrome_options = Options()
    chrome_options.add_argument("--headless")
    chrome_options.add_argument("--use-fake-ui-for-media-stream")
    driver = webdriver.Chrome(executable_path="C:\Users\uqiabde1\Downloads\chromedriver.exe", options = chrome_options)
    return driver


def getNumber(driver):
    # Step 1: Go to website
    driver.get(f"https://vemcount.app/embed/widget/uOCRuLPangWo5fT?locale=en")
    # wait for the element to load
    try:
        WebDriverWait(driver, 10).until(lambda s: s.find_element_by_id("flex items-center").is_displayed())
    except TimeoutException:
        print("TimeoutException: Element not found")
        return None

    # Step 2: Create a parse tree of page sources after searching
    soup = BeautifulSoup(driver.page_source, "lxml")
    # Step 3: Iterate over the search result and fetch the number
    for number in soup.select("div.items-center"):
        number_needed = "p span"
        print({
            "title": number.select_one(number_needed).text,
        })

# create the driver object.
driver = configure_driver()
getNumber(driver)
# close the driver.
driver.close()

我在 chromedriver 中收到以下错误

[0414/150051.086:INFO:CONSOLE(2)] "The AudioContext was not allowed to start. It must be resumed (or created) after a user gesture on the page. https://goo[dot]gl/7K7WLu", source: https://vemcount.app/build/embed.js?id=2ff0173dd78c5c1f99c6 (2)

我不确定使用哪个 chrome_option 来绕过这个错误。我尝试了一些，例如

--no-user-gesture-required

和

--disable-gesture-requirement-for-presentation

非常感谢您的帮助。谢谢。

Answer 1

以防万一您有相同的查询或正在努力进行动态网络抓取，我找到了一种无需使用 selenium 和 bs4.

即可抓取数据的方法

我使用了 playwright，它更直接，并且有一个非常受欢迎的 inner_html() 函数，可以直接读取动态 flex HTML 代码。这里是参考代码。

#part of the help to write the script I got from 

from playwright.sync_api import sync_playwright

with sync_playwright() as p:
    browser = p.chromium.launch(slow_mo=1000)

    page = browser.new_page()
    page.goto('https://vemcount.app/embed/widget/uOCRuLPangWo5fT')
    central = page.query_selector("p.w-full span");
    print({'central': central.inner_html()})
        
    browser.close()

如果有更好的方法，我很乐意听取您的建议。

你的，

Python 的初学者。 :)

Selenium chromedriver error: The AudioContext was not allowed to start. It must be resumed (or created) after a user gesture on the page

Selenium chromedriver error: The AudioContext was not allowed to start. It must be resumed (or created) after a user gesture on the page

python

selenium

selenium-chromedriver

selenium-webdriver