将顶点作为行聚合到字符串

Question

我在 Oracle 18c table.

中将多段折线顶点存储为单独的行

ASSET_ID     PART_NUM VERTEX_NUM          X          Y          M
---------- ---------- ---------- ---------- ---------- ----------
001                 1          1          0          5          0
001                 1          2         10         10      11.18
001                 1          3         30          0      33.54
001                 2          1         50         10      33.54
001                 2          2         60         10      43.54

示例数据： db<>fiddle

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我想将行聚合成一个文本值（不带单引号）：

'MULTILINESTRING ((0 5 0, 10 10 11.18, 30 0 33.54),(50 10 33.54, 60 10 43.54))'

我如何使用 Oracle SQL 做到这一点？

Answer 1

使用Listagg函数

with cte as (
select 001 c1,1 c2,1 c3,0 c4,5 c5,0 c6 from dual union all
select 001,1,2,10,10,11.18 from dual union all
select 001,1,3,30,0,33.54 from dual union all
select 001,2,1,50,10,33.54 from dual union all
select 001,2,2,60,10,43.54 from dual
), cte1 as
(
select c2,listagg(c4||' '||c5||' '||c6,',')  
s1 from cte group by c2 order by c2 asc)
select 'MULTILINESTRING ('||listagg('('||s1||')',',') 
within group (order by c2) ||')' as result from cte1;

fiddle