我如何在 Django 中重构这个模型？

Question

我想从 Django 重构这个模型（代码），这样我就可以根据需要获取尽可能多的输入，而无需编写大量代码或高效地进行。或者我可以在模型中使用 for 循环吗？

models.py

class Sales(models.Model):
    customer = models.ForeignKey(Customer,on_delete=models.CASCADE)
    prescribed_doctor = models.CharField(blank=True,max_length=150)
    date_created = models.DateTimeField(default=timezone.now)
    sales_medicine_1 = models.ForeignKey(Medicines,related_name='sales_medicine',on_delete=models.CASCADE)
    Med_quantity_1 = models.IntegerField(blank=False,default=1)
    Free_quantity_1 = models.IntegerField(blank=True,default=0,null=True)
    margin_1 = models.PositiveIntegerField(blank=True,default=0,null=True)
    discount_1 = models.FloatField(choices=dis,default=0,null=True)
    discount_1_amt = models.FloatField(default=0,null=True)
    rate_1 = models.FloatField(blank=True,default=0,null=True)
    batch_no_1 = models.CharField(null=True,blank=True,max_length=50)
    mfg_1 = models.CharField(max_length=50,blank=True,null=True)
    expiry_1 = models.CharField(max_length=20,null=True,blank=True)
    sales_medicine_2 = models.ForeignKey(Medicines,blank=True,null=True,related_name='sales_medicine_1',on_delete=models.CASCADE)
    Med_quantity_2 = models.IntegerField(blank=True,default=0,null=True)
    Free_quantity_2 = models.IntegerField(blank=True,default=0,null=True)
    margin_2 = models.PositiveIntegerField(blank=True,default=0,null=True)
    discount_2 = models.FloatField(choices=dis,default=0,null=True)
    discount_2_amt = models.FloatField(default=0,null=True)
    rate_2 = models.FloatField(blank=True,default=0,null=True)
    batch_no_2 = models.CharField(null=True,blank=True,max_length=50)
    mfg_2 = models.CharField(max_length=50,blank=True,null=True)
    expiry_2 = models.CharField(max_length=20,null=True,blank=True)
    sales_medicine_3 = models.ForeignKey(Medicines,blank=True,null=True,related_name='sales_medicine_2',on_delete=models.CASCADE)
    Med_quantity_3 = models.IntegerField(blank=True,default=0,null=True)
    Free_quantity_3 = models.IntegerField(blank=True,default=0,null=True)
    margin_3 = models.PositiveIntegerField(blank=True,default=0,null=True)
    discount_3 = models.FloatField(choices=dis,default=0,null=True)
    discount_3_amt = models.FloatField(default=0,null=True)
    rate_3 = models.FloatField(blank=True,default=0,null=True)
    batch_no_3 = models.CharField(null=True,blank=True,max_length=50)
    mfg_3 = models.CharField(max_length=50,blank=True,null=True)
    expiry_3 = models.CharField(max_length=20,null=True,blank=True)
    Payment_status = models.CharField(max_length=15,choices=payment_status)
    Paid_amount = models.FloatField(blank=True,default=0,null=True)
    auto_generated = models.BooleanField(default=False)

Answer 1

我得到了解决方案 - 只需使用 ManytoManyField()。

class Sales(models.Model):
    customer = models.ForeignKey(Customer, on_delete=models.CASCADE)
    prescribed_doctor = models.CharField(blank=True, max_length=150)
    date_created = models.DateTimeField(default=timezone.now)
    sales_medicine = models.ManytoManyField(Medicines)

这是 Django 中多对多关系的文档：https://docs.djangoproject.com/en/4.0/topics/db/examples/many_to_many/

我如何在 Django 中重构这个模型？

How can I refactor this model in Django?

python

django

refactoring

for-loop

django-models