pop() 采用 1 个位置参数，但为最大堆栈问题给出了 2 个

Question

我遇到了上面提到的错误 pop() 需要 1 个位置参数，但是在我运行 .pop() 命令时给出了 2 个用于最大堆栈问题，例如max_stack.pop(1000).

我不太确定我的语法出了什么问题。感谢有人可以指导我解决这个问题。

class MaxStack():
    
    def __init__(self):
        #main stack for enqueue operation
        self.main_stack =[]
        # another stack for dequeue oepration
        self.max_stack = []
        
    # adding an item to the queue is O(1) operation
    def push(self, data):
        
        #push new item to the stack
        self.main_stack.append(data)
        
        # first item is the same in both stacks
        if (len(self.main_stack) == 1):
            self.max_stack.append(data)
            return
        
        #if the item is the biggest one in the main stack, we add it to the max stack
        #stack[-1] is the peak operation: returns the last item we have inserted (without removing any elements)
        if (data > self.max_stack[-1]):
            self.max_stack.append(data)
        
        # if not larger number in the comparison then we duplicate the largest element from the max stack
        else:
            self.max_stack.append(self.max_stack[-1])
                                  
    #getting items
    def pop(self):
        self.max_stack.pop()
        self.main_stack.pop()
        return

    # max item is the last item we have inserted into the maxStack O(1)
    def get_max_item(self):
        return self.max_stack.pop()
    
if __name__ == "__main__":
    max_stack = MaxStack()

Answer 1

pop 不向 self（调用实例）提供任何额外参数，因此您可以不提供任何参数。

如果您希望 pop(1000) 执行某些操作，则必须将其实现为 pop(self, your_param)。

pop() 采用 1 个位置参数，但为最大堆栈问题给出了 2 个

pop() takes 1 positional argument but 2 were given for maximum stack problem

python

python-3.x

stack