打印调用该函数的文件的文件名的函数

Question

我想创建一个日志函数，记录调用日志函数的文件的名称，后跟我要记录的消息 'message'

functions.py

def log(text):
    print(os.path.basename(__file__)+": "+text)

main.py

log('message')

这个returns:

functions.py: message

我想要 return:

main.py: message

Answer 1

您可以首先使用 inspect module and retrieving the name of the path to caller's file, and then extracting the file's name from that (which is very easy using the pathlib 模块通过解释器的堆栈返回。

main.py:

from functions import log

log('message')

functions.py:

import inspect
from pathlib import Path

def log(text):
    caller_path = Path(inspect.stack()[1][1])
    print(f'{caller_path.name}: {text}')

打印调用该函数的文件的文件名的函数

Function to print the file name of the file that is calling the function

python

logging

filenames

file