如何在语音识别成绩单上执行正则表达式？

Question

我的申请摘要：

输入：让用户对着电脑说话（询问电脑"What is your name?"）✅
对 'transcript' 结果执行正则表达式（来自 webkitSpeechRecognition） ❌
输出：console.log("My name is Harry Johnson")。 ❌

我正在尝试对语音识别记录执行正则表达式，如下所示：

var speechRecognition = window.SpeechRecognition || window.webkitSpeechRecognition; 
var recognition = new webkitSpeechRecognition();

var transcript;

recognition.addEventListener('result', e => {
     transcript = Array.from(e.results)
        .map(result => result[0])
        .map(result => result.transcript)
        .join('');
    console.log(transcript);
});

recognition.addEventListener('end',recognition.start);


window.addEventListener('DOMContentLoaded', function() {
    document.getElementById("speak_button").addEventListener('click', function() {
        recognition.start();
    });
});

以上工作正常，我能够 console.log 来自用户的 transcript/speech。问题来自以下代码，我认为这与成绩单必须是字符串这一事实有关？我已经尝试使用 String(transcript) 和 transcript.toString() 将成绩单转换为字符串，但我仍然没有实现我的结果：这是让计算机 console.log “我的名字是哈里·约翰逊".

function speakBackToMe() {

/*regular expression that will match words in the transcript */
    var person_name_regex = /what is your name|(?=.*\byour\b)(?=.*\bfull\b)(?=.*\bname\b)|(?=.*\btell\b)(?=.*\bme\b)(?=.*\byour\b)(?=.*\bname\b)|(?=.*\bcan\b)(?=.*\btell\b)(?=.*\bme\b)(?=.*\byour\b)(?=.*\bname\b)|(?=.*\btell\b)(?=.*\bme\b)(?=.*\byour\b)(?=.*\bfull\b)(?=.*\bname\b)|(?=.*\blet\b)(?=.*\bknow\b)(?=.*\bfull\b)(?=.*\bname\b)|(?=.*\bgrab\b)(?=.*\byour\b)(?=.*\bname\b)|(?=.*\bwhat\b)(?=.*\byour\b)(?=.*\bname\b)|(?=.*\bshare\b)(?=.*\bme\b)(?=.*\bfull\b)(?=.*\bname\b)|(?=.*\bwhat\b)(?=.*\byour\b)(?=.*\bfirst\b)(?=.*\band\b)(?=.*\blast\b)(?=.*\bname\b)/ig;
   
/*if regular expression matches all words, then function will be performed*/
    if (person_name_regex.test(transcript)) {
        console.log("My name is Harry Johnson");
        
}

}

speakBackToMe();

正则表达式是正确的，主要问题是 transcript 变量。如果有人对为什么不执行 console.log("My name is Harry Johnson") 函数有任何建议，请与我分享，我们将不胜感激！ :)

谢谢！

Answer 1

对我来说，我只是把 speakBackToMe(); console.log（成绩单）下方的行；在结果事件侦听器块中并且有效

recognition.addEventListener('result', e => {
     transcript = Array.from(e.results)
        .map(result => result[0])
        .map(result => result.transcript)
        .join('');
    console.log(transcript);
    speakBackToMe();
});

如何在语音识别成绩单上执行正则表达式？

How to perform regular expressions on a Speech Recognition transcript?

javascript

speech-recognition

webkit