将矩阵转换为 R 中的 3 列数据帧

Question

我有一个矩阵，例如：

     G1       G2       G3       G4
G1   0.000000 3.575791 3.961912 4.102760
G2   3.575791 0.000000 4.515661 4.656509
G3   3.961912 4.515661 0.000000 2.114352
G4   4.102760 4.656509 2.114352 0.000000

（输出格式）

structure(c(0, 3.5757909, 3.9619119, 4.1027599, 3.5757909, 0, 
4.515661, 4.656509, 3.9619119, 4.515661, 0, 2.114352, 4.1027599, 
4.656509, 2.114352, 0), .Dim = c(4L, 4L), .Dimnames = list(c("G1", 
"G2", "G3", "G4"), c("G1", "G2", "G3", "G4"
)))

我想将其转换为：

C1 C2 Value
G1 G1 0.000000
G1 G2 3.575791
G1 G3 3.961912
G1 G4 4.102760
G2 G2 0.000000
G2 G3 4.515661
G2 G4 4.656509
G3 G3 0.000000
G3 G4 2.114352
G4 G4 0.000000

Answer 1

我们可以将 matrix 转换为 table 然后使用 as.data.frame （如果我们不想要 upper.tri 或 lower.tri，请更改它到 NA 然后重塑)

m1[upper.tri(m1)] <- NA
out <- na.omit(as.data.frame.table(m1))
names(out) <- c("C1", "C2", "Value")

-输出

> out
   C1 C2    Value
1  G1 G1 0.000000
2  G2 G1 3.575791
3  G3 G1 3.961912
4  G4 G1 4.102760
6  G2 G2 0.000000
7  G3 G2 4.515661
8  G4 G2 4.656509
11 G3 G3 0.000000
12 G4 G3 2.114352
16 G4 G4 0.000000

将矩阵转换为 R 中的 3 列数据帧

transform matrix to 3 column dataframe in R

r

dplyr