如何在不创建新列表的情况下将此列表拆分为同一个列表

Question

如何拆分此列表

['charmander|4/16/2022 18:5:52|Good to see you!', 'charmander|4/16/2022 18:6:0|Good to see you!']

至

['charmander', '4/16/2022 18:5:52', 'Good to see you!' , 'charmander', '4/16/2022 18:5:52', 'Good to see you!']

顺便说一下，这个列表是一个 txt 文件的一部分，并且已经通过这样做拆分了

file = open('messages/' + username + '.txt', 'r')

data = file.read().strip()

results = data.split("\n")

Answer 1

你可以这样使用 string.split("|")

l = ['charmander|4/16/2022 18:5:52|Good to see you!', 'charmander|4/16/2022 18:6:0|Good to see you!']
newList = []
for val in l:
    newList += (val.split("|"))

Output:
['charmander',
 '4/16/2022 18:5:52',
 'Good to see you!',
 'charmander',
 '4/16/2022 18:6:0',
 'Good to see you!']

Answer 2

也许你可以试试 list-comprehension:

with open(f'messages/{username}.txt', 'r') as file:
    data = file.read().strip()
results = [s.split('|') for s in data.split('\n')]
print(results)

输出：

['charmander', '4/16/2022 18:5:52', 'Good to see you!' , 'charmander', '4/16/2022 18:5:52', 'Good to see you!']

如何在不创建新列表的情况下将此列表拆分为同一个列表

how to i split this list into the same list without creating new list

python

list

split