Unix

Question

我有 2 个脚本 test1.sh & test2.sh，下面是定义。同样

猫test1.sh


DUP_CHK=`beeline --showHeader=false --outputformat=tsv2 -e "select count(*) from table1"`

echo "$DUP_CHK"
export DUP_CHK

猫test2.sh

#!/bin/bash


source ./test1.sh

cnt_chk="$DUP_CHK"
cnt_chk_2=`beeline --showHeader=false --outputformat=tsv2 -e "select count(*) from table1"`

echo "$DUP_CHK"
echo "$cnt_chk"
echo "$cnt_chk_2"

if "$cnt_chk -eq $cnt_chk_2"
     then
       echo "You are right"
       exit 0
else
    echo "Something is not right, check"
    exit  0
fi

我传递的两个值相同，但是错误抛出为 test2.sh: line 18: 100 -eq 100: command not found

我在这里错过了什么。想法??谢谢

Answer 1

你需要

  if((cnt_chk == cnt_chk2))

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