如果提示为空,如何停止js脚本
How to stop js script if prompt is blank
所以我正在开发一款仅使用警报和提示的游戏。如果提示中没有文本,我一直无法让游戏停止。有人可以帮忙吗?这是我的代码。
<div class="snippet" data-lang="js" data-hide="false" data-console="true" data-babel="false">
<div class="snippet-code">
<pre><code>var food = 20;
var happy = 20;
var sleep = 20;
function setup(){
var input1 = prompt("Welcome to pet sim\r\nYour pet\'s food stat is "+food+", happy stat is "+happy+", and sleep stat is "+sleep+".\r\nWhat would you like to do?\r\n\"food\" \"play\" \"sleep\"");
if(input1="food"){
food++;
alert("Food eaten");
setup();
}else if(input1=null){
void(0);
}
}
setup();
所以我正在开发一款仅使用警报和提示的游戏。如果提示中没有文本,我一直无法让游戏停止。有人可以帮忙吗?这是我的代码。
<div class="snippet" data-lang="js" data-hide="false" data-console="true" data-babel="false">
<div class="snippet-code">
<pre><code>var food = 20;
var happy = 20;
var sleep = 20;
function setup(){
var input1 = prompt("Welcome to pet sim\r\nYour pet\'s food stat is "+food+", happy stat is "+happy+", and sleep stat is "+sleep+".\r\nWhat would you like to do?\r\n\"food\" \"play\" \"sleep\"");
if(input1="food"){
food++;
alert("Food eaten");
setup();
}else if(input1=null){
void(0);
}
}
setup();