如何在单词的特定索引之间洗牌中间字母？

Question

这是我目前所掌握的

mounted() {
  const randomVariants = [...Array(3)].map(() =>
    this.baseWord
      .split('')
      .sort(() => 0.5 - Math.random())
      .join('')
  )
  const variantsWithoutInitialWord = randomVariants.filter(
    (word) => word !== this.baseWord // !== this.baseWord , it  removes if baseWord  present
  )
  this.result = [...new Set(variantsWithoutInitialWord)] // removing duplicates
},

我需要一个字符串值的多个值。喜欢“橙色”，并生成多个喜欢：

“华丽”
“俄勒冈州”
“奥格兰”

前两个字符和最后一个字符相同。它只会改变其他字符，我还需要一个原始值。 lik "xy.........z" 只有x, y 和 z 是静态的，而其他内部字符将随机打乱。

Answer 1

这应该很好用

<template>
  <div>
    <p>
      The idea is to have a string, with it's first 2 indexes and last one
      untouched while all the others indexes are shuffled
    </p>
    <pre>combination found for string '{{ baseWord }}'</pre>
    <pre>actual list: {{ results }}</pre>
  </div>
</template>

<script>
const shuffledMiddleLetters = (array) =>
  array
    .split('')
    .sort(() => 0.5 - Math.random())
    .join('')

const wordMiddlePart = (word) => word.slice(2, word.length - 1)

export default {
  data() {
    return {
      baseWord: 'watermelon',
      results: [],
    }
  },
  mounted() {
    const shuffledMiddleLettersVariants = [...Array(50)].map(() =>
      shuffledMiddleLetters(wordMiddlePart(this.baseWord))
    )

    const dedupedVariants = [
      ...new Set([
        wordMiddlePart(this.baseWord),
        ...shuffledMiddleLettersVariants,
      ]),
    ]
    this.results = dedupedVariants.map((dedupedVariants) =>
      [
        this.baseWord.slice(0, 2),
        dedupedVariants,
        this.baseWord[this.baseWord.length - 1],
      ].join('')
    )
  },
}
</script>

这是它的样子

如何在单词的特定索引之间洗牌中间字母？

How to shuffle middle letters in between specific indexes of a word?

javascript

vue.js

nuxt.js