Jenkins shell 不在 Seed DSL 生成的作业中工作

Jenkins shell not working from within Seed DSL generated Job

Groovy、闭包和 Jenkins 的新手。

我创建了一个种子作业:

def Job1 = 'FromTemplate-testJob'
job {
    name Job1
    steps {
       shell( "echo Hello > out5.txt" )
       shell( "/c echo custard > op4.txt")
    }
}

如预期成功创建了包含 2 个 shell 命令的子作业:

echo Hello > out5.txt
/c echo custard > op4.txt

然而,当 运行 时,这个创建的作业显然 运行 成功,输出如下:

Started by user anonymous
Building in workspace C:\Program Files (x86)\Jenkins\jobs\FromTemplate-testJob\workspace
[workspace] $ C:\Windows\system32\cmd.exe -xe C:\Windows\TEMP\hudson3852539874278383422.sh
Microsoft Windows [Version 6.1.7601]
Copyright (c) 2009 Microsoft Corporation.  All rights reserved.

C:\Program Files (x86)\Jenkins\jobs\FromTemplate-testJob\workspace>[workspace] $ C:\Windows\system32\cmd.exe -xe C:\Windows\TEMP\hudson1697067517687695305.sh
Microsoft Windows [Version 6.1.7601]
Copyright (c) 2009 Microsoft Corporation.  All rights reserved.

C:\Program Files (x86)\Jenkins\jobs\FromTemplate-testJob\workspace>Finished: SUCCESS

然而,这两个输出文件都不是在任何地方创建的。 shell 可执行文件定义为:

 C:\Windows\system32\cmd.exe

我不明白什么?

shell dsl command is translated to "Execute shell" build step, which usually is used on Unix-like systems. You have to use batchFile dsl 命令,因此它将被转换为 "Execute Windows batch command" 构建步骤,用于 Windows:

def Job1 = 'FromTemplate-testJob'
job {
    name Job1
    steps {
        batchFile( "echo Hello > out5.txt" )
        batchFile( "echo custard > op4.txt" )
    }
}