将蛇形大小写转换为驼峰大小写，直到使用 sed 的特殊字符

Question

我正在尝试将 Localizable.strings 的密钥从 Mac 上的蛇形外壳转换为驼峰外壳。我可以使用 gsed，因为它支持 \U 大写。

我的文件如下所示：

/* Title  */
"home.title" = "Welcome";

/* Email  */
"home.signup_email" = "Email";

/* recover_email  */
"home.signup_email_recover" = "Recover Email";

/* password  */
"home.password" = "Enter your __Password__:";

我希望修改此文件以获得此：

/* Title  */
"home.title" = "Welcome";

/* Email  */
"home.signupEmail" = "Email";

/* recover_email  */
"home.signupEmailRecover" = "Recover Email";

/* password  */
"home.password" = "Enter your __Password__:";

我尝试将 gsed 与类似的东西一起使用，但不幸的是，我无法在 = 字符之后停止。

find . -name "*.strings" | xargs gsed -i -e '/=/! s/_\([a-z]\)/\U/gi'

知道如何在 = 之后停止替换 _ 吗？

谢谢！

Answer 1

您可以使用

sed ':a;s/^\([^=]*\)_\([[:alpha:]]\)/\U\E/;ta'

如果您只想替换 _ + 小写字母，您也可以使用 [[:lower:]] 而不是 [[:alpha:]]。

详情:

:a - 设置一个 a 标签
s/^\([^=]*\)_\([[:alpha:]]\)/\U\E/ - 找到除 = 字符以外的任何零个或多个字符并将其捕获到第 1 组中，然后匹配 _ 然后将任何字母捕获到组中，然后替换第 1 组 + 第 1 组中的大写字母
ta - 如果替换成功，则跳回到 a 标签位置。

参见 online demo:

#!/bin/bash
s='/* Title  */
"home.title" = "Welcome";
 
/* Email  */
"home.signup_email" = "Email";
 
/* recover_email  */
"home.signup_email_recover" = "Recover Email";
 
/* password  */
"home.password" = "Enter your __Password__:";

/* One more string */
"my_string_key" = "[Click here](https://my.url.com/deeplink?id=UUID&section_id=foo)";'
sed ':a;s/^\([^=]*\)_\([[:alpha:]]\)/\U\E/;ta' <<< "$s"

输出：

/* Title  */
"home.title" = "Welcome";
 
/* Email  */
"home.signupEmail" = "Email";
 
/* recoverEmail  */
"home.signupEmailRecover" = "Recover Email";
 
/* password  */
"home.password" = "Enter your __Password__:";

/* One more string */
"myStringKey" = "[Click here](https://my.url.com/deeplink?id=UUID&section_id=foo)";

Answer 2

有点冗长，但这里有一个 non-regex 方法，使用 OSX 上可用的默认 BSD awk：

awk '
BEGIN {FS=OFS="="}
NF == 2 && (n = split(, a, /_/)) {
   s = a[1]
   for (i=2; i<=n; ++i)
      s = s toupper(substr(a[i], 1, 1)) substr(a[i], 2)
    = s
} 1' file

/* Title  */
"home.title" = "Welcome";

/* Email  */
"home.signupEmail" = "Email";

/* recover_email  */
"home.signupEmailRecover" = "Recover Email";

/* password  */
"home.password" = "Enter your __Password__:";

Answer 3

如果您不介意 gnu gawk 特定的解决方案：

           # always true condition whether
           # ORS contains empty string
           #
  gawk    '(ORS=toupper(substr(RT,2)))~_'     RS='_[a-z]' file
or
           #     +ORS is always 0/false,
           # so !+ORS is always 1/ true
           #
  gawk  '!+(ORS=toupper(substr(RT,2)))'       RS='_[a-z]' file
or
  gawk 'sub(/$/,toupper(substr(RT,2)))' ORS=  RS='_[a-z]' file
or
           # this just means 
           # 0-to-0th-power
           #
  gawk 'FS^(ORS=toupper(substr(RT,2)))'       RS='_[a-z]' file  
or
           # ASCII string-compare that is always true since
           # underscore "_" has higher byte ordinance than
           # either empty string or any ASCII uppercase letters
           #
  gawk '(ORS=toupper(substr(RT,2)))<RS'       RS='_[a-z]' file

=

/* Title  */
"home.title" = "Welcome";

/* Email  */
"home.signupEmail" = "Email";

/* recoverEmail  */
"home.signupEmailRecover" = "Recover Email";

/* password  */
"home.password" = "Enter your __Password__:";

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