如何在 Python 中获取以分钟为单位的时差

Question

我有一个时间表示形式，格式为字符串：

9:00 am
8:45 pm

例如，12 小时制，无前导小时 0，am/pm 后缀

我需要得到当时和现在之间的时差（以分钟为单位）。

时间总是在未来，所以如果现在是 09:00，9:10 am 是 10 分钟后，8:50 am 是 23 小时 50 分钟后。

我一直在玩 strptime 但我似乎无法弄清楚如何以兼容的格式获取我的解析时间和 now() 来进行算术运算。

Answer 1

很可能有更适合的模块。但是你可以快速而肮脏地做：

def to_minutes(time_str)
    time, suffix = time_str.split(" ")
    hours, min = time.split(":")
    if suffix == "pm":
        hours+=12
    min = hours*60+min
    return min

time1 = to_minuntes("9:00 am")
time2 = to_minutes("8:45 pm")

diff = time2-time1
if diff < 0:
    diff+= 24*60
    
# and if necessary you can do a 
hours = diff //60
minutes = diff % 60

if hours > 0:
    final_diff = f"{hours}h {minutes}min"
else:
    final_diff = f"{minutes}min"

Answer 2

像这样，确实有 strptime:

from datetime import datetime

timeString1 = "9:00 am"
timeString2 = "8:45 pm"

format = '%I:%M %p'
datetime1 = datetime.strptime(timeString1, format)
datetime2 = datetime.strptime(timeString2, format)

minutes_diff = (datetime2 - datetime1).total_seconds() / 60.0

print(f"the time difference in minutes is: {minutes_diff}")

Answer 3

这是使用 datetime 的变体。

格式字符串FMT = "%I:%M %p"根据strptime#time.strftime. and as only datetime objects support differences, i use those only (using datetime.combine)选择。

from datetime import datetime, timedelta

FMT = "%I:%M %p"
TODAY_DATE = datetime.today().date()

def to_datetime(t_str):
    return datetime.combine(TODAY_DATE, datetime.strptime(t_str, FMT).time())

NOW = to_datetime("9:00 am")
for t_str in ("9:10 am", "8:45 pm"):
    t = to_datetime(t_str)
    if t < NOW:
        t += timedelta(days=1)
    print(f"{t_str}, {(t - NOW)}, {(t - NOW).total_seconds() / 60:.0f} min")

它输出：

9:10 am, 0:10:00, 10 min
8:45 pm, 11:45:00, 705 min

如何在 Python 中获取以分钟为单位的时差

How to get time difference in mins in Python

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