在 Python 代码中使用 REST EPA 会出现错误 此代码有什么问题?

Using REST EPA in Python code gives an error What is wrong with this code?

REST API 文档

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curl --location --request POST 'https://zaya.io/api/v1/links' \
--header 'Content-Type: application/x-www-form-urlencoded' \
--header 'Authorization: Bearer {api_key}' \
--data-urlencode 'url={url}'
-----------------------------------------------------------------

我的代码

import requests
api="https://zaya.io/api/v1/links"
API_KEY = "################################################"
data = "https://en.wikipedia.org/wiki/Python_(programming_language)"
headers = {'Authorization': 'Bearer ' + API_KEY}
r = requests.get(api, data=data, headers=headers)
print(response.text)

我遇到的错误:

{"message":"You are not logged in.","status":403} 
  • 错误 1 ​​您正在执行 GET,文件要求您发送 POST.
  • 错误 2 数据必须采用 URL 编码形式,必须 key-value 对
  • 错误3 你必须设置正确的Content-Type header
  • 更大的错误不要在public论坛上post你的API键。

经过上述更正,下面的代码工作正常。

import requests

api = "https://zaya.io/api/v1/links"

# Never reveal your API key
API_KEY = "##########################################################"

# Data is URL Form encoded, so it must be key-value pair
data = {"url": "https://en.wikipedia.org/wiki/Python_(programming_language)"}

# Add proper headers
headers = {'Authorization': 'Bearer ' + API_KEY, 'Content-Type': 'application/x-www-form-urlencoded'}

# Most important. CURL says POST, you did GET 
r = requests.post(api, data=data, headers=headers)
print(r.text)
# Gives proper response