我将如何合并或区分 GitLab ci cd yaml 脚本文件的两个 yml 文件？

Question

我有 GitLab ci/cd yaml 文件脚本

services:
  - docker:19.03.11-dind
workflow:
  rules:
    - if: $CI_COMMIT_BRANCH == $CI_DEFAULT_BRANCH || $CI_COMMIT_BRANCH == "developer" || $CI_COMMIT_BRANCH == "stage"|| ($CI_COMMIT_BRANCH =~ (/^([A-Z]([0-9][-_])?)?SPRINT(([-_][A-Z][0-9])?)+/i))
      when: always
    - if: $CI_COMMIT_BRANCH != $CI_DEFAULT_BRANCH || $CI_COMMIT_BRANCH != "developer" || $CI_COMMIT_BRANCH != "stage"|| ($CI_COMMIT_BRANCH !~ (/^([A-Z]([0-9][-_])?)?SPRINT(([-_][A-Z][0-9])?)+/i))
      when: never 
stages:
  - build
  - Publish
  - deploy
cache:
  paths:
    - .m2/repository
    - target
build_jar:
  image: maven:3.8.3-jdk-11
  stage: build
  script: 
    - mvn clean install package -DskipTests=true
  artifacts:
    paths:
      - target/*.jar
docker_build:
  stage: Publish
  image: docker:19.03.11
  services:
    - docker:19.03.11-dind
  variables:
    IMAGE_TAG: $CI_REGISTRY_IMAGE:$CI_COMMIT_SHORT_SHA
  script: 
    - docker login -u $CI_REGISTRY_USER -p $CI_REGISTRY_PASSWORD $CI_REGISTRY
    - docker build -t $IMAGE_TAG .
    - docker push $IMAGE_TAG
deploy_dev:
  stage: deploy
  image: stellacenter/aws-helm-kubectl
  before_script:
    - aws configure set aws_access_key_id ${DEV_AWS_ACCESS_KEY_ID}
    - aws configure set aws_secret_access_key ${DEV_AWS_SECRET_ACCESS_KEY}
    - aws configure set region ${DEV_AWS_DEFAULT_REGION}
  script:
    - sed -i "s/<VERSION>/${CI_COMMIT_SHORT_SHA}/g" provider-service-dev.yml    
    - mkdir -p  $HOME/.kube
    - cp $KUBE_CONFIG_DEV $HOME/.kube/config
    - chown $(id -u):$(id -g) $HOME/.kube/config 
    - export KUBECONFIG=$HOME/.kube/config
    - kubectl apply -f provider-service-dev.yml
  only:
    - developer 
deploy_stage:
  stage: deploy
  image: stellacenter/aws-helm-kubectl
  before_script:
    - aws configure set aws_access_key_id ${DEV_AWS_ACCESS_KEY_ID}
    - aws configure set aws_secret_access_key ${DEV_AWS_SECRET_ACCESS_KEY}
    - aws configure set region ${DEV_AWS_DEFAULT_REGION}
  script:
    - sed -i "s/<VERSION>/${CI_COMMIT_SHORT_SHA}/g" provider-service-stage.yml    
    - mkdir -p  $HOME/.kube
    - cp $KUBE_CONFIG_STAGE $HOME/.kube/config
    - chown $(id -u):$(id -g) $HOME/.kube/config 
    - export KUBECONFIG=$HOME/.kube/config
    - kubectl apply -f provider-service-stage.yml
  only:
    - stage

我把这个 yaml 脚本合并成两个分支，即 developer 和 stage 但我有两个 yml 文件用于单独的分支（用于开发人员和阶段）

提供商服务-dev.yml

   apiVersion: apps/v1
kind: Deployment
metadata:
  name: provider-app
  namespace: stellacenter-dev
  labels:
    app: provider-app
spec:
  replicas: 1
  selector:
    matchLabels:
      app : provider-app
  template:
    metadata:
      labels:
        app: provider-app
    spec:
      containers:
      - name: provider-app
        image: registry.gitlab.com/stella-center/backend-services/provider-service:<VERSION>
        imagePullPolicy: Always
        ports:
          - containerPort: 8092
      imagePullSecrets:
        - name:  gitlab-registry-token-auth

---

apiVersion: v1
kind: Service
metadata:
  name:  provider-service
  namespace: stellacenter-dev
spec:
  type: NodePort
  selector:
    app:  provider-app
  ports:
  - port:  8092
    targetPort:  8092

提供商服务-stage.yml

   apiVersion: apps/v1
kind: Deployment
metadata:
  name: provider-app
  namespace: stellacenter-stage-uat
  labels:
    app: provider-app
spec:
  replicas: 1
  selector:
    matchLabels:
      app : provider-app
  template:
    metadata:
      labels:
        app: provider-app
    spec:
      containers:
      - name: provider-app
        image: registry.gitlab.com/stella-center/backend-services/provider-service:<VERSION>
        imagePullPolicy: Always
        ports:
          - containerPort: 8092
      imagePullSecrets:
        - name:  gitlab-registry-token-auth

---

apiVersion: v1
kind: Service
metadata:
  name:  provider-service
  namespace: stellacenter-stage-uat
spec:
  type: NodePort
  selector:
    app:  provider-app
  ports:
  - port:  8092
    targetPort:  8092

我在gitlab cicd yaml脚本中单独提到了但是它显示了类似

的错误

$ kubectl apply -f provider-service-dev.yml
Error from server (NotFound): error when creating "provider-service-dev.yml": namespaces "stellacenter-dev" not found
Error from server (NotFound): error when creating "provider-service-dev.yml": namespaces "stellacenter-dev" not found
Cleaning up project directory and file based variables
00:01
ERROR: Job failed: exit code 1

它在脚本的最后一行显示错误。它表明找不到命名空间，但那只是存在的。我不知道如何解决这个问题。请帮我整理一下

Answer 1

如果我正确理解你的问题，你可以通过编辑这个 stage 并添加 one variable : CI_COMMIT_BRANCH

Docker 构建命令类似于：docker build -t $IMAGE_TAG -f $CI_COMMIT_BRANCH .

docker_build:
  stage: Publish
  image: docker:19.03.11
  services:
    - docker:19.03.11-dind
  variables:
    IMAGE_TAG: $CI_REGISTRY_IMAGE:$CI_COMMIT_SHORT_SHA
  script: 
    - docker login -u $CI_REGISTRY_USER -p $CI_REGISTRY_PASSWORD $CI_REGISTRY
    - docker build -t $IMAGE_TAG -f $CI_COMMIT_BRANCH .
    - docker push $IMAGE_TAG

所以现在您必须将两个 docker 文件都保留在存储库中，但是只需根据分支名称更改这些文件的名称即可。

developer:
    FROM maven:3.8.3-jdk-11 AS MAVEN_BUILD
    COPY pom.xml /build/
    COPY src /build/src/
    WORKDIR /build/
    RUN mvn clean install package -DskipTests=true
    FROM openjdk:11
    WORKDIR /app
    COPY --from=MAVEN_BUILD /build/target/provider-service-*.jar /app/provider-service.jar
    ENV PORT 8092
    EXPOSE $PORT
    ENTRYPOINT ["java","-Dspring.profiles.active=development","-jar","/app/provider-service.jar"]

和

stage:
    FROM maven:3.8.3-jdk-11 AS MAVEN_BUILD
    COPY pom.xml /build/
    COPY src /build/src/
    WORKDIR /build/
    RUN mvn clean install package -DskipTests=true
    FROM openjdk:11
    WORKDIR /app
    COPY --from=MAVEN_BUILD /build/target/provider-service-*.jar /app/provider-service.jar
    ENV PORT 8092
    EXPOSE $PORT
    ENTRYPOINT ["java","-Dspring.profiles.active=stage","-jar","/app/provider-service.jar"]

Answer 2

rules:variables: 可能很适合这个用例。您可以使用 rules: 更改环境变量。使用它根据分支名称设置 dockerfile 的位置。将此变量传递给 docker build 中的 -f 标志，使其使用该 dockerfile。

docker_build:
  rules:
    - if: $CI_COMMIT_BRANCH == $CI_DEFAULT_BRANCH
      variables:
        DOCKERFILE_PATH: "Dockerfile"
    - if: '"$CI_COMMIT_BRANCH == "stage"'
      variables:
        DOCKERFILE_PATH: "staging.Dockerfile"
    # and so on
  script:
    # ...
    - echo "Building dockerfile: ${DOCKERFILE_PATH}"
    - docker build -t registry.tld/myimage:latest -f "$DOCKERFILE_PATH" .

我将如何合并或区分 GitLab ci cd yaml 脚本文件的两个 yml 文件？

How will I combine or differentiate the two yml files for GitLab ci cd yaml script file?

gitlab

yaml

gitlab-ci

gitlab-ci-runner

gitlab-api