枢轴模式下的累积数据
Accamulated data in pivot mode
现在我通过 row_cumsum
累积列
test
| project Boenheter, Ar, Maned, ManedTLA
| extend _date = make_datetime(toint(Ar), Maned, 1)
| extend key1 = Ar, __auto0 = datetime_part('Month', startofmonth(_date))
| summarize value0 = sum(Boenheter) by key1, __auto0, ManedTLA
| order by __auto0 asc, key1 asc
| serialize value0 = **row_cumsum(value0, __auto0 != prev(__auto0))**
| extend __p = pack(tostring(ManedTLA), value0)
| summarize __p = make_bag(__p) by key1
| evaluate bag_unpack(__p)
| order by key1 asc
但我想在下一种方法中对行进行累积：
Feb = Jan + Feb, Mar = Jan + Feb + Mar, 依此类推...所以 Feb = 304, Mar = 624（以 2012 年为例）等等
Kusto 是否有一些技巧可以对行而不是列进行累积 (row_cumsum)？
请帮忙）
使用 row_cumsum，在使用 pivot
之前重新启动年份更改
// Generation of a data sample. No part of the solution.
let t = materialize(range i from 1 to 200 step 1 | extend dt = ago(365d*10*rand()));
// The solution starts here.
t
| summarize count() by year = getyear(dt), month = format_datetime(dt,'MM')
| order by year asc, month asc
| extend cumsum = row_cumsum(count_, year != prev(year))
| evaluate pivot(month, any(cumsum), year)
year
01
02
03
04
05
06
07
08
09
10
11
12
2012
2
4
6
7
10
14
16
2013
2
3
7
8
10
11
15
16
17
18
2014
2
7
11
12
13
14
15
17
19
20
2015
2
3
6
10
11
12
13
14
15
2016
1
2
3
5
6
8
10
11
12
15
16
19
2017
1
2
5
8
13
16
17
20
21
2018
4
5
8
12
15
18
20
23
24
25
26
2019
5
7
8
10
11
14
18
19
20
21
2020
2
5
8
10
11
13
15
16
19
22
2021
2
5
6
7
8
9
11
17
2022
2
4
5
现在我通过 row_cumsum
累积列test
| project Boenheter, Ar, Maned, ManedTLA
| extend _date = make_datetime(toint(Ar), Maned, 1)
| extend key1 = Ar, __auto0 = datetime_part('Month', startofmonth(_date))
| summarize value0 = sum(Boenheter) by key1, __auto0, ManedTLA
| order by __auto0 asc, key1 asc
| serialize value0 = **row_cumsum(value0, __auto0 != prev(__auto0))**
| extend __p = pack(tostring(ManedTLA), value0)
| summarize __p = make_bag(__p) by key1
| evaluate bag_unpack(__p)
| order by key1 asc
但我想在下一种方法中对行进行累积： Feb = Jan + Feb, Mar = Jan + Feb + Mar, 依此类推...所以 Feb = 304, Mar = 624（以 2012 年为例）等等
Kusto 是否有一些技巧可以对行而不是列进行累积 (row_cumsum)？
请帮忙）
使用 row_cumsum，在使用 pivot
// Generation of a data sample. No part of the solution.
let t = materialize(range i from 1 to 200 step 1 | extend dt = ago(365d*10*rand()));
// The solution starts here.
t
| summarize count() by year = getyear(dt), month = format_datetime(dt,'MM')
| order by year asc, month asc
| extend cumsum = row_cumsum(count_, year != prev(year))
| evaluate pivot(month, any(cumsum), year)
| year | 01 | 02 | 03 | 04 | 05 | 06 | 07 | 08 | 09 | 10 | 11 | 12 |
|---|---|---|---|---|---|---|---|---|---|---|---|---|
| 2012 | 2 | 4 | 6 | 7 | 10 | 14 | 16 | |||||
| 2013 | 2 | 3 | 7 | 8 | 10 | 11 | 15 | 16 | 17 | 18 | ||
| 2014 | 2 | 7 | 11 | 12 | 13 | 14 | 15 | 17 | 19 | 20 | ||
| 2015 | 2 | 3 | 6 | 10 | 11 | 12 | 13 | 14 | 15 | |||
| 2016 | 1 | 2 | 3 | 5 | 6 | 8 | 10 | 11 | 12 | 15 | 16 | 19 |
| 2017 | 1 | 2 | 5 | 8 | 13 | 16 | 17 | 20 | 21 | |||
| 2018 | 4 | 5 | 8 | 12 | 15 | 18 | 20 | 23 | 24 | 25 | 26 | |
| 2019 | 5 | 7 | 8 | 10 | 11 | 14 | 18 | 19 | 20 | 21 | ||
| 2020 | 2 | 5 | 8 | 10 | 11 | 13 | 15 | 16 | 19 | 22 | ||
| 2021 | 2 | 5 | 6 | 7 | 8 | 9 | 11 | 17 | ||||
| 2022 | 2 | 4 | 5 |