将 Bash 命令的结果存储在 Shell 变量中
Store Result of Bash Command in Shell Variable
我正在尝试将 bash 命令的结果存储在 for 循环中以供命令使用。这是我目前拥有的:
for filename in /home/WIN/USER/files/*
var=$(basename ${filename%.*}) | awk -F'[_.]' '{print }'
do echo var
done
但是,我收到了这些错误:
./script.sh: line 2: syntax error near unexpected token `var=$(basename ${filename%.*})'
./script.sh: line 2: `var=$(basename ${filename%.*}) | awk -F'[_.]' '{print }''
有谁知道如何解决这个问题或如何做我想做的事?
谢谢。
你的for
语句是错误的,你的变量赋值语句也是错误的。你应该这样写:
for filename in /home/WIN/USER/files/*; do
var=$( your shell code goes here ) # you assign the output of the shell code here
echo $var # you echo the results here
done
我正在尝试将 bash 命令的结果存储在 for 循环中以供命令使用。这是我目前拥有的:
for filename in /home/WIN/USER/files/*
var=$(basename ${filename%.*}) | awk -F'[_.]' '{print }'
do echo var
done
但是,我收到了这些错误:
./script.sh: line 2: syntax error near unexpected token `var=$(basename ${filename%.*})'
./script.sh: line 2: `var=$(basename ${filename%.*}) | awk -F'[_.]' '{print }''
有谁知道如何解决这个问题或如何做我想做的事?
谢谢。
你的for
语句是错误的,你的变量赋值语句也是错误的。你应该这样写:
for filename in /home/WIN/USER/files/*; do
var=$( your shell code goes here ) # you assign the output of the shell code here
echo $var # you echo the results here
done