使用 Javascript 将数组转换为嵌套对象结构

Question

我正在尝试使用 Javascript 将一个对象数组转换为一个嵌套对象结构，但结果并不如预期。我在下面解释我的代码。

let data = [
        {
            "hop_no": 1,
            "jumphost_id": "jumphost1"
        },
        {
            "hop_no": 2,
            "jumphost_id": "jumphost2"
        },
        {
            "hop_no": 3,
            "jumphost_id": "another-jumphost"
        },
        {
            "hop_no": 4,
            "jumphost_id": "last-jumphost"
        }
    ]
let result ='';

for(let i = 0; i< data.length; i++) {
   const index = i+1;
   const obj = data.find(o => o.name === index);
   if(result === '' && !result['host-id']) {
      result = {
          "host-id": obj.jumphost_id,
          "next-hop":{}
      }
   }else{
     if(result['next-hop'] === '') {
        result['next-hop'] = obj.jumphost_id
     }
   }
}

这里给出了对象数组i.e- data，下面给出了我预期的结构。

低于预期结果。

{
                    "host-id": "jumphost1",
                    "next-hop": {
                        "host-id": "jumphost2",
                        "next-hop": {
                            "host-id": "another-jumphost",
                            "next-hop": {
                                "host-id": "last-jumphost",
                            }
                        }
                    }
                }

这里的条件是当 "hop_no": 1 相应的 jumphost_id 值将分配给 host-id 并且将成为第一个键。之后，嵌套对象结构将按 hop_no 值的升序排列，相应的 jumphost_id 值将分配给 next-hop 键。任何人都可以帮助我仅使用 Javascript 设计此结构。

Answer 1

您可以尝试从内到外构建对象。

像这样：

let data = [
        {
            "hop_no": 1,
            "jumphost_id": "jumphost1"
        },
        {
            "hop_no": 2,
            "jumphost_id": "jumphost2"
        },
        {
            "hop_no": 3,
            "jumphost_id": "another-jumphost"
        },
        {
            "hop_no": 4,
            "jumphost_id": "last-jumphost"
        }
    ]
let result = {};
for (var i = data.length - 1; i >= 0; i--) {
    let tmp = {
      'host-id': data[i]['jumphost_id'],
    };
    if (Object.keys(result).length !== 0) {
       tmp['next-hop'] = result;
    }
    result = tmp;
}
console.log(result);

Answer 2

您可以使用 reduce 函数执行此操作：

let data = [{
    "hop_no": 1,
    "jumphost_id": "jumphost1",
    ip: "",
    port: 22,
    user: "",
    password: "",
    "device-type": "linux"
  },
  {
    "hop_no": 2,
    "jumphost_id": "jumphost2",
    ip: "",
    port: 22,
    user: "",
    password: "",
    "device-type": "linux"
  },
  {
    "hop_no": 3,
    "jumphost_id": "another-jumphost",
    ip: "",
    port: 22,
    user: "",
    password: "",
    "device-type": "linux"
  },
  {
    "hop_no": 4,
    "jumphost_id": "last-jumphost",
    ip: "",
    port: 22,
    user: "",
    password: "",
    "device-type": "linux"
  }
]

let result = data.sort((a, b) => b.hop_no - a.hop_no).reduce((prev, curr, i, array) => {
  let { hop_no, jumphost_id, ...rest } = curr
  return {
    'host-id': jumphost_id,
    ...rest,
    ...(i > 0 ? {'next-hop': { ...prev }} : {}),
  }
}, {})

console.log(result)

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