如何压缩原始类型数组的输出？

Question

我的 json 文件包含整数数组、字符串数组和对象。有没有一种方法可以压缩仅包含整数或字符串的数组的输出？

要么不显示这些数组的元素，要么
显示元素类型和数量

这是现在的样子：

$ jq "." foo.json
{
    "version": [
            "2.53.0",
            "2.53.0",
            "2.53.0",
            "2.53.0",
            "2.53.0",
            "2.53.3",
            "2.53.3",
            "2.53.0",
            "2.53.0",
            "2.53.3",
            "2.53.0",
            "2.53.0",
            "2.53.3",
            "2.53.0",
            "2.53.0",
            "2.53.0",
            "2.53.0",
            "2.53.0",
            "2.53.3",
            "2.53.0"
          ],
    "walltime_seconds": [
            0.165,
            0.199,
            0.415,
            0.193,
            12.114,
            0.227,
            12.341,
            12.145,
            0.135,
            0.326,
            0.293,
            0.19,
            0.271,
            0.103,
            0.196,
            0.18,
            0.177,
            0.166,
            0.506,
            0.568
          ]
}

这就是我想要的：

{
    "version": "[..]",
    "walltime_seconds": "[..]",

}

或这个

{
    "version": "Array(str, 20)",
    "walltime_seconds": "Array(float, 20)",

}

当然，压缩应该发生在 json 树中的任何地方，并且应该只对 int、str、float 而不是对象进行压缩。

Answer 1

这样做就可以了：

def compress:
  if type == "array"
  then (if    all(.[]; type == "string") then "[string]"
        elif  all(.[]; type == "number") then "[number]"
        elif  all(.[]; type == "boolean") then "[boolean]"
        else .
        end)
  else .
  end;

walk(compress)

根据您的示例输入，结果将是：

{
  "version": "[string]",
  "walltime_seconds": "[number]"
}

包括null的长度和句柄数组：

def compress:
  def check($t):
    if all(.[]; type == $t) then "[\($t)[\(length)]]" else empty end;
  if type == "array"
  then check("string") // check("number") // check("boolean") // check("null") // .
  else .
  end;

如何压缩原始类型数组的输出？

How to compress output of arrays of primitive type?

arrays

json

jq

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