MYSQL - select 行基于条件，否则 select 其他行

Question

我有一个 table 产品，它与 product_prices 有关联。 每个产品在不同国家可以有多个价格。

期望的结果：当我运行查询时，我想收到所有基于国家条件[=46]的单一价格的所有产品=].

Logic

1. If product has price for the specified country-> then country price will be displayed.
2. If product does not have price for the specified country-> then price for with country_id 400 needs to be displayed.
3. If product has no price for specified country and for country with id 400 -> then the price with country_id 500 needs to be displayed.
4. If product has not price for specified country and id 400, and id 500 -> then price which has country with biggest amount of total users will be displayed.

我为 1 个单一产品做了类似的事情。但我不知道如何为所有产品实现这些。

select p.id, pp.price, pp.country_id,
(CASE WHEN (pp.country_id=:countryId) then 0 else
    (CASE WHEN (pp.country_id=400) then 1 else
        (case when (pp.country_id=500) then 2 else 3 END) END) END) as priorityIndex
from products p
inner join product_prices pp on p.id = pp.product_id
inner join countries c on pp.country_id = c.id
where p.id = '00057c218b154d5b838b928a0189ff9f'
order by priorityIndex limit 1;

我的数据： 国家/地区 table

country_id	country_code	total_users
2	FR	10
10	US	100
27	UK	200
400	EU	160
500	GLOBAL	150

产品价格table

product_id	price_id	price	country_id
product1	1a	19.99	27
product1	1b	20.99	400
product1	1c	30.99	500
product2	2a	199.99	10
product2	2b	299.99	400
product3	3a	50.99	500
product4	4a	40	2
product4	4a	45	10

插入国家/地区 27 时我的预期输出：

product_id	price	country_id
product1	19.99	27
product2	20.99	400
product3	50.99	500
product4	45	10

---

我做了这样的事情。但我不确定只有最后一部分。如果需要根据经销商总数选择产品价格。

select A.id, A.price_id, A.price, A.country from
(select p.id, pp.id as price_id, pp.price, pp.country_id as country,
        ROW_NUMBER() over (PARTITION BY p.id order by (CASE WHEN (pp.country_id=:countryId) then 0 else
            (CASE WHEN (pp.country_id=400) then 1 else
                (case when (pp.country_id=500) then 2 else 3 END) END) END), c.total_dealer_users desc) AS rowNumber
 from products p
          inner join product_prices pp on p.id = pp.product_id
          inner join countries c on pp.country_id = c.id
 where p.id in ('00057c218b154d5b838b928a0189ff9f','054a8caf911e4ff3a594990af20a9611')) as A
where rowNumber=1;

Answer 1

使用 MySQL 8.0+ ROW_NUMBER() 允许删除每个产品的第一行除外的所有行：

SELECT * FROM (
    SELECT p.id, 
        pp.price,
        pp.country_id,
        ROW_NUMBER() OVER (PARTITION BY p.id ORDER BY FIELD(pp.country_id, 500, 400, 27) DESC) AS `rn`
    FROM products AS p
        JOIN product_prices AS pp
            ON p.id = pp.product_id
    WHERE p.id IN (...)
) AS t WHERE t.rn=1

Answer 2

SELECT
  *
FROM
(
  SELECT
    pp.product_id,
    pp.price_id,
    pp.price,
    pp.country_id as country,
    ROW_NUMBER() OVER (
      PARTITION BY pp.product_id
          ORDER BY FIELD(
                     c.country_id,
                     27,
                     400,
                     500,
                     c.country_id
                   ),
                   c.total_users DESC
    )
      AS rowNumber
  FROM
    product_price   pp
  INNER JOIN
    country         c
      ON pp.country_id = c.country_id
)
  AS ranked_price
WHERE
  rowNumber=1;

https://dbfiddle.uk/?rdbms=mysql_8.0&fiddle=94f8851be7f309d8c4fd1946230d7999