获取 Apache 错误代码并将其显示在 PHP 中

Get the Apache error code and display it in PHP

我正在制作一个 PHP 错误页面,我想知道是否有任何方法可以获取导致错误的错误代码并显示它。然后,我可以使用相同的方法,但让 PHP 根据发生的错误显示不同的错误代码。我在 PHP 5.6.10 中使用 Apache 2.4。任何帮助将不胜感激。

将所有错误页面指向 .htaccess 中的一个位置

ErrorDocument 400 /error.php
ErrorDocument 401 /error.php
ErrorDocument 403 /error.php
ErrorDocument 404 /error.php
ErrorDocument 500 /error.php

然后在error.php你可以这样做:

<?php
$status = $_SERVER['REDIRECT_STATUS'];
$codes = array(
       403 => array('403 Forbidden', 'The server has refused to fulfill your request.'),
       404 => array('404 Not Found', 'The document/file requested was not found on this server.'),
       405 => array('405 Method Not Allowed', 'The method specified in the Request-Line is not allowed for the specified resource.'),
       408 => array('408 Request Timeout', 'Your browser failed to send a request in the time allowed by the server.'),
       500 => array('500 Internal Server Error', 'The request was unsuccessful due to an unexpected condition encountered by the server.'),
       502 => array('502 Bad Gateway', 'The server received an invalid response from the upstream server while trying to fulfill the request.'),
       504 => array('504 Gateway Timeout', 'The upstream server failed to send a request in the time allowed by the server.'),
);

$title = $codes[$status][0];
$message = $codes[$status][1];
if ($title == false || strlen($status) != 3) {
       $message = 'Please supply a valid status code.';
}
// Insert headers here
echo '<h1>'.$title.'</h1>
<p>'.$message.'</p>';
// Insert footer here

来自https://css-tricks.com/snippets/php/error-page-to-handle-all-errors/

--

如果您想为 ex 自定义错误消息。解析错误,您可以将其添加到 PHP 文件的顶部:

<?php
set_error_handler('errorHandler');
function errorHandler($code, $msg, $file, $line) {

    header($_SERVER['SERVER_PROTOCOL'] . ' 500 Internal Server Error', true, 500);
    echo "<h1>Unexpected error occurred</h1><p>The request was unsuccessful due to an unexpected error.</p>";
    // PHP error message:
    echo "<p>$msg</p>";
    die();
}