Sum/Aggregate 2 个最小值，因此 total2 将 > 2

Question

我有这个 table，如果 total2 <=2，我需要聚合 code1。基本上将它 up/combine total 滚动到下一个值 least value 以便字段 total2 将是 >2 。我怎样才能在 t-sql 中做到这一点？感谢您的任何帮助。我对此很困惑。

原始：

https://dbfiddle.uk/?rdbms=sqlserver_2019&fiddle=ad7f47b37d4694411b8a38db07356a7e

code1	code2	total1	total2
AAA1	123	9	3
AAA1	120	3	5
AAA1	124	4	2
AAA2	125	2	1
AAA2	126	3	2
AAA3	121	4	4
AAA5	119	1	1
AAA6	118	4	2
AAA6	117	2	5

汇总：

code1	code2	total1	total2
AAA1	120	3	5
AAA1	123+124	13	5
AAA2	125+126	5	3
AAA3	121	4	4
AAA5	119	1	1
AAA6	118+117	6	7

Answer 1

首先需要根据total2确定最少的2行。您可以使用 row_number()

row_number() over(partition by code1 order by total2)

确定 grp 后，对其执行聚合（仅针对最少的 2 行 grp 2）

对于total1和total2，使用SUM()，对于code2，因为是字符串，使用字符串聚合string_agg()

示例数据：

code1	code2	total1	total2
AAA1	123	9	3
AAA1	120	3	5
AAA1	124	4	2
AAA2	125	2	1
AAA2	126	3	2
AAA3	121	4	4
AAA5	119	1	1
AAA6	118	4	2
AAA6	117	2	5

with cte as
(
    select    *, 
              grp = case when row_number() over(partition by code1 
                                                    order by total2) <= 2
                         then 2
                         else 1
                         end
       from   Test1
)
select code1,
       code2 = case when grp = 1 then max(code2)
                    else string_agg(code2, '+') within group (order by code2)
                    end,
       total1 = case when grp = 1 then max(total1) else sum(total1) end,
       total2 = case when grp = 1 then max(total2) else sum(total2) end       
from   cte
group by code1, grp
order by code1, grp

结果：

code1	code2	total1	total2
AAA1	120	3	5
AAA1	123+124	13	5
AAA2	125+126	5	3
AAA3	121	4	4
AAA5	119	1	1
AAA6	117+118	6	7

fiddle<> demo

Sum/Aggregate 2 个最小值，因此 total2 将 > 2

Sum/Aggregate the 2 least values so that total2 will be > 2

tsql